Answer:
<em>m=2.551 kg</em>
Explanation:
Gravitational Potential Energy (GPE)
Energy is the capacity that a body has to do work due to any of its characteristics as speed, height, temperature, and many other physical magnitudes. The GPE is the one that depends on the relative height h that a body of mass m has respect to a given reference, and can be computed as
GPE=m.g.h
The bowler uses 50 Joules of energy to lift the ball by 2 meters, we can know the mass of the ball by solving the above equation for m
42.9°
Explanation:
Let's assume that the x-axis is aligned with the incline and the positive direction is up the incline. We can then apply Newton's 2nd law as follows:
Note that the net force is zero because the block is moving with a constant speed when the angle of the incline is set at Solving for the angle, we get
or
Average speed is difined as the total distance travelled divided by the total time required to cover the distance. Mathematically, it is expressed as:
To obtain the average speed of Daniel, we shall determine the distance travelled in each case. This is illustrated below:
<h3>Case 1:</h3>Speed 1 (S₁) = 6 mph
Time 1 (t₁) = 0.8 h.
<h3>Distance 1 (D₁) =? </h3>Cross multiply
D₁ = 6 × 0.8
<h3>D₁ = 4.8 mile</h3><h3>Case 2:</h3>Speed 2 (S₂) = 2 mph
Time 2 (t₂) = 1.2 h.
<h3>Distance 2 (D₂) =? </h3>Cross multiply
D₂ = 2 × 1.2
<h3>D₂ = 2.4 mile </h3>Next, we shall determine the total time. This can be obtained as follow:
Time 1 (t₁) = 0.8 h.
Time 2 (t₂) = 1.2 h.
<h3>Total time (T) =? </h3>T = t₁ + t₂
T = 0.8 + 1.2
<h3>T = 2 h</h3>Next, we shall determine the total distance. This can be obtained as follow:
Distance 1 (D₁) = 4.8 mile
Distance 2 (D₂) = 2.4 mile
<h3>Total distance (D) =?</h3>D = D₁ + D₂
D = 4.8 + 2.4
<h3>D = 7.2 mile</h3>Finally, we shall determine the average speed of Daniel. This can be obtained as follow:
Total time = 2 h
Total distance = 7.2 mile
<h3>Average speed =?</h3>Therefore, the average speed of Daniel is 3.6 mph
Learn more: brainly.com/question/680492
Answer:
a) number of copper atoms 65 (⁶⁵Cu) is 7.692 10⁶ atoms
b) m_total Cu = 1.585 10⁹ u = 2.632 10⁻¹⁸ kg
Explanation:
a) For this exercise let's start by using the radioactive decay ratio
N = N₀ o e - lambda t
The half-life time is defined as the time it takes for half of the radioactive (activated) atoms to decay, therefore after two half-lives there are
N = ½ (½ N₀) = ¼ N₀
N₀ = 4 N
in each decay a photon is emitted so we can use a direct rule of proportions. If an atom emits a photon it has Eo = 1,04 Mev, how many photons it has energy E = 10,000 MeV
# _atoms = 1 atom (photon) (E / Eo)
# _atoms = 1 10000 / 1.04
# _atoms = 9615,4 atoms
N₀ = 4 #_atoms
N₀ = 4 9615,4
N₀= 38461.6 atoms
in the exercise indicates that half of the atoms decay in this way and the other half decays directly to the base state of Zinc, so the total number of activated atoms
N_activated = 2 # _atoms
N_activated = 2 38461.6
N_activated = 76923.2
also indicates that 1% = 0.01 of the nuclei is activated by neutron bombardment
N_activated = 0.01 N_total
N_total = N_activated / 0.01
N_total = 76923.2 / 100
N_total = 7.692 10⁶ atoms
so the number of copper atoms 65 (⁶⁵Cu) is 7.692 10⁶
b) the natural abundance of copper is
⁶³Cu 69.17%
⁶⁵Cu 30.83%
Let's use a direct proportion rule. If there are 7.692 10⁶ ⁶⁵Cu that represents 30.83, how much ⁶³Cu is there that represents 69.17%
# _63Cu = 69.17% (7.692 10⁶ / 30.83%)
# _63Cu = 17.258 10⁶ atom ⁶³Cu
the total amount of comatose is
#_total Cu = #_ 65Cu + # _63Cu
#_total Cu = (7.692 + 17.258) 10⁶
#_total Cu = 24.95 10⁶
the atomic mass of copper is m_Cu = 63.546 u
m_total = #_totalCu m_Cu
m_total = 24.95 10⁶ 63,546 u
m_total = 1.585 10⁹ u
let's reduce to kg
m_total Cu = 1.585 10⁹ u (1,66054 10⁻²⁷ kg / 1 u)
m_total Cu = 2.632 10⁻¹⁸ kg