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garri49 [273]
3 years ago
6

What is, x is at most 30 inequality

Mathematics
1 answer:
Leya [2.2K]3 years ago
4 0
The answer would be x \ge 30
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Write 0.0002507 in scientific notation.
Serggg [28]

Answer:

2.507* 10^-4

Step-by-step explanation:

0.0002507

We need to have one number to the left of the decimal

We move the decimal 4 places to the right

Since we moved the decimal to the right, the exponent on the power of 10 is negative

2.507* 10^-4

7 0
3 years ago
Solve the exponential equation: 6–2x = 62 – 3x
eduard

Answer:

the answer should be 56 :)

Step-by-step explanation:

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3 years ago
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Write an equation: The sides of a rectangle are x and ( x - 4 ). The perimeter is 87
Svetlanka [38]

The perimeter of a rectangle, is all of the sides added up.

In a rectangle, there are two widths (right and left), and two lengths (up and down)

So:

Perimeter = 2 × width + 2 × length.

To get the equation we just substitute in the values that we are given:

length = (x)

width = (x - 4)

perimeter = 87

So just put these values into:  perimeter = 2 × width + 2 × length:

87  =  2(x) + 2(x - 4)

_____________________________

Answer:

The equation is:       87 = 2(x) + 2(x - 4)

<em>(note: this can be simplified down like so:</em>

<em>87 = 2x + 2x - 8</em>

<em>87 = 4x - 8</em>

<em>95 = 4x</em>

23.75 = x    

)

5 0
3 years ago
Find an equation of the parabola with vertex (2, -1) and directrix y=-7.
Brums [2.3K]

Answer:

the answer to this is y=7x-15

7 0
3 years ago
A passenger train traveled 180 miles in the same amount of time it took a freight train to travel 120 miles. The rate of the fre
Mnenie [13.5K]

Answer:

The passenger train is moving at 45 miles per hour

Step-by-step explanation:

Let the amount of time it took the two trains to travel the distance = t.

Since the two trains traveled the distance at the same time,

Rate of the passenger train =\frac{180}{t}

Rate of the freight train = \frac{120}{t}

<em>Where t is in hours.</em>

From the problem, we can see that the rate of the freight train was 15 miles per hour slower than the rate of the passenger train. Mathematically, we can represent this as

\frac{120}{t}= \frac{180}{t}-15

from the above equation, we can now get our value for t  as

\frac{120-180}{t}=-15\\\frac{-60}{t}=-15\\t=4 hours

We have our time of travel for the two trains as 4 hours.

The rate of the passenger train can now be calculated by 180/4 = 45 miles per hour

5 0
4 years ago
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