Let p (x) = 4x^4-13x^2-2x
The zero of x-2 is 2
putting x = 2 in p (x), we get,
p (2) = 4×2^4-13×2^2-2×2
= 64 - 52 - 4
= 64 - 56
= 8
Therefore, remainder = 8
Is there a problem or something to show for it?
Answer: a) 0.9961, b) 0.9886
Step-by-step explanation:
Since we have given that
Probability that does not show up = 0.10
Probability that show up = 0.90
Here, we use "Binomial distribution":
n = 125 and p = 0.90
Number of passengers that hold in a flight = 120
a) What is the probability that every passenger who shows up can take the flight?
(b) What is the probability that the flight departs with empty seats?
Hence, a) 0.9961, b) 0.9886
Answer:
102/526
Step-by-step explanation:
This would be the answer because when u add the amount of freshman plus sophomore plus juinior and plus senior, you get the result of 526. so that would be the denominator while the number of seniors would be the numerator...
So point slope form is y=mx+b where m=slope and b=y intercept so
in (x,y) form
one solution is x=1 and y=3, also slope is 2 so
m=2
subsitute
3=2(1)+b
3=2+b
subtract 2
1=b
equation is
y=2x+1
tricky answers so simplify them
A: y-1=2(x-3)
distribute
y-1=2x-6
add 1
y=2x-5
not the answer
B: y-3=2(x-1)
distribute
y-3=2x-2
add 3
y=2x+1
correct
the answer is B
