A shark is swimming at 10 m/s west when it spots some floating bait caught in some seaweed straight ahead. After 10 s, and trave
2 answers:
Answer:
C. 0.5 m/s² west
Explanation:
The shark average acceleration is given by the following equation:
where:
u = 10 m/s west is the initial velocity of the shark
v = 15 m/s west is the final velocity
t = 10 s is the time taken
Plugging numbers into the formula, we find
and the direction is west, because the shark speeds up in the same direction of the initial velocity, so the acceleration is positive and therefore in the same direction.
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Answer:
speed when it reaches y = 4.00cm is
v = 14.9 g.m/s
Explanation:
given
q₁=q₂ =2.00 ×10⁻⁶
distance along x = 3.00cm= 3×10⁻²
q₃= 4×10⁻⁶C
mass= 10×10 ⁻³g
distance along y = 4×10⁻²m
r₁ = =
= 3.61cm = 0.036m
r₂ = =
= 5cm = 0.05m
electric potential V =
change in potential ΔV =
ΔV = , where
2.00μC
ΔV =
ΔV = 2 × 9×10⁹ × 2×10⁻⁶ ×
ΔV= 2.789×10⁵
= ΔV × q₃
ˣ 10×10⁻³ ×v² = 2.789×10⁵× 4 ×10⁻⁶
v² = 223.12 g.m/s
v = 14.9 g.m/s