The gravitational potential energy is 252 J
Explanation:
The Gravitational Potential Energy (GPE) of an object is given by
where
W is the weight of the object
h is the height of the object above the ground
For the carriage and the baby in this problem, we have
W = 21 N is their weight
h = 21 m is their height above the ground
Substituting,
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Answer:
(1) The maximum air temperature is 1383.002 K
(2) The rate of heat addition is 215.5 kW
Explanation:
T₁ = 17 + 273.15 = 290.15
T₂ = 290.15 × 3.17767 = 922.00139
Therefore,
T₃ = T₂×1.5 = 922.00139 × 1.5 = 1383.002 K
The maximum air temperature = T₃ = 1383.002 K
(2)
Therefore;
Q₁ = 1.005(1383.002 - 922.00139) = 463.306 kJ/jg
Heat rejected per kilogram is given by the following relation;
= 0.718×(511.859 - 290.15) = 159.187 kJ/kg
The efficiency is given by the following relation;
Where:
β = Cut off ratio
Plugging in the values, we get;
Therefore;
Heat supplied =
Therefore, heat supplied = 215491.064 W
Heat supplied ≈ 215.5 kW
The rate of heat addition = 215.5 kW.
Answer:
Lifting force, F = 21240 N
Explanation:
It is given that,
Mass of the helicopter, m = 1800 kg
It rises with an upward acceleration of 2 m/s². We need to find the lifting force supplied by its rotating blades. It is given by :
F = mg + ma
Where
mg is its weight
and "ma" is an additional acceleration when it is moving upwards.
So,
F = 21240 N
So, the lifting force supplied by its rotating blades is 21240 N. Hence, this is the required solution.