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3 years ago

8

_ consist of silicon chips and an antenna that can transmit data to a wireless receiver while ___ need to be scanned manuall

y and read individually

1 answer:

Anna11 [10]3 years ago

6 0

<u>A Radio Receiver</u> consist of silicon chips and an antenna that can transmit data to a wireless receiver while the <u>signal </u>need to be scanned manually and read individually

Explanation:

<u>A Radio Receiver</u> consist of silicon chips and an antenna that can transmit data to a wireless receiver while th<u>e signal</u> need to be scanned manually and read individually

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Why might it be necessary to ignore some of the data points just before and just after the collision?

krek1111 [17]

We have no idea. We need to examine the experimental set-up. You've given us no information, except that there may have been some sort of collision.

7 0

3 years ago

An object of mass, m1 with a velocity, v1 collides with another object at rest (v2 = 0) with a mass, m2. After the collision, m1

goblinko [34]

Answer:

$v"_{1} = v_{1} tan$ Θ

$v^{"} _{2} = \frac{m_{1}v_{1}}{m_{2}cos}$ Θ

Θ = $tan^{-1}(\frac{v^{"} _{1} }{v_{1} } )$

Explanation:

Applying the law of conservation of momentum, we have:

Δ $p_{x = 0}$

$p_{x} = p"_{x}$

$m_{1}v_{1} = m_{2}v"_{2} cos$ Θ (Equation 1)

Δ $p_{y} = 0$

$p_{y} = p"_{y}$

$0 = m_{1} v"_{1} - m_{2} v"_{2} sin$ Θ (Equation 2)

From Equation 1:

$v"_{2} = \frac{m_{1}v_{1}}{m_{2}cos}$ Θ

From Equation 2:

$m_{2} v"_{2}$ sinΘ = $m_{1} v_{1}$

$v"_{1} = \frac{m_{2} v"_{2}sinΘ}{m_{1} }$

Replacing Equation 3 in Equation 4:

$v"_{1}=\frac{m_{2}\frac{m_{1}v_{1}}{m_{2}cosΘ}sinΘ}{m_{1}}$

$v"_{1}=v_{1}\frac{sinΘ}{cosΘ}$

$v"_{1}=v_{1}tan$ Θ (Equation 5)

And we found Θ from the Equation 5:

tanΘ= $\frac{v"_{1}}{v_{1}}$

Θ= $tan^{-1}(\frac{v"_{1}}{v_{1}})$

7 0

3 years ago

A child jumps from a moving sled with a speed of 2.2 m/s and in the

butalik [34]

The initial velocity of the sled will be 7.34 m/sec. V is the initial velocity of the sled.

<h3>What is the law of conservation of momentum?</h3>

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

The given data in the problem is;

(m₁) mass of child = 38 kg

(u₁) is the initial velocity child = 2.2 m/s

(m₂) is the mass of sled = 68 kg

(u₂) is the initial velocity of sled = ?

(v) is the velocity after collision = 5.5 m/s

According to the law of conservation of momentum;

Momentum before collision =Momentum after collision

$\rm m_1u_1 + m_2u_2 = v(m_1 + m_2)\\\\(38 \times 2.2) + (68 \times V) = 5.5 \times (38+68) \\\\ 83.6 + 68V = 5.5 \times 106 \\\\ 83.6 + 68V =583 \\\\ \rm 68\ V= 583 -83.6 \\\\ \rm 68 \ V= 499.4\\\\ V= 7.34 \ m/sec$

Hence,the initial velocity of the sled will be 7.34 m/sec.

To learn more about the law of conservation of momentum refer;

brainly.com/question/1113396

#SPJ1

4 0

2 years ago

Spaceship flies past mars with a speed of 0.985c rela- tive to the surface of the planet. when the spaceship is directly overhea

galben [10]

The proper time would be the time measured in the rest frame of the event, so in this case the observer on mars would measure the proper time.

8 0

3 years ago

What is the magnitude and direction of an electric field that exerts a 2.00 * 10^-5 N upward force on a −1.5 μC charge?

Over [174]

The relation between electric field intensity, electric force and charge is given as follow,

$E = \frac{F}{q}$

Where,

F = Force

q = Charge

The direction of force on a charge placed in an electric field is same as the direction of electric field if the charge has positive polarity and opposite if charge has negative polarity.

Replacing we have that

$E = \frac{2*10^{-5}N}{-1.5*10^{-6}C}$

$E = -13.3N/C$

As direction of force is upward and polarity of charge is negative, hence the direction of field will be opposite to that of force. Therefore direction of field is downward.

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3 years ago