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VMariaS [17]
3 years ago
8

Which is an example of an unstructured activity that promotes resistance training?

Physics
1 answer:
aleksandrvk [35]3 years ago
3 0
One possible unstructured activity that promotes resistance training would be climbing playground equimpent - A. 

This is by nature a unstructured ctivity. Furthermore, it promotes resistance training because you're forced to move and pull and push yourself. 
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What is the relationship between the acceleration of an object change in relation to its mass
yarga [219]

The relationship between mass and acceleration is an inverse proportionality

Explanation:

The relationship between the acceleration of an object and its mass is given by Newton's second law, which states that:

F=ma

where

F is the net force on the object

m is its mass

a is its acceleration

From the equation, we notice that if the force on the object is kept constant, then the mass and the acceleration are inversely proportional to each other. This means that:

  • If the mass of the object is increased, its acceleration will decrease
  • If the mass of the object is decreased, its acceleration will increase

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

3 0
3 years ago
A rock has 750 J of potential energy as it sits on a ledge. If the rock were pushed off the ledge, how much would it have just b
wariber [46]

Answer:

the 750 j will have potential energy is 375

Explanation:

750/2 is 375

8 0
2 years ago
50 points for this please help
Softa [21]

but the points are only 25

7 0
3 years ago
Read 2 more answers
A bullet with mass 0.04000 kg, traveling at a speed of 310.0 m/s, strikes a stationary block of wood having mass 6.960 kg. The b
ch4aika [34]

Answer:

1.77 m/s

Explanation:

From the law of conservation of momentum,

Total momentum before collision = Total momentum after collision

mu+m'u' = V(m+m')............................ Equation 1

Where m = mass of the bullet, m' = mass of the block, u = initial velocity of the bullet, u' = initial velocity of the block, V = Velocity of the bullet-wood combination immediately after collision

make V the subject of the equation

V = (mu+m'u')/(m+m').................. Equation 2

Given: m = 0.04 kg, m' = 6.96 kg, u = 310 m/s, u' = 0 m/s (stationary)

Substitute into equation 2

V = (0.04×310+6.96×0)/(0.04+6.96)

V = 12.4/7

V = 1.77 m/s

Hence the speed, in m/s, of the bullet-plus-wood combination immediately after the collision is 1.77 m/s

6 0
3 years ago
When Carbon -14 decays into Nitrogen -14, what kind of decay is this?
Nutka1998 [239]

Answer:

me no speak d english

Explanation:

3 0
3 years ago
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