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3 years ago

What is responsible for the hole in the ozone layer?

Physics

2 answers:

Vaselesa [24]3 years ago

5 0

CFCs, carbon dioxide, green house gases and it's effects are responsible for the hole in ozone layer.

babymother [125]3 years ago

4 0

Answer: The depletion of the ozone layer is due to CFC (chloro fluoro carbon) which is widely used in air conditioner and refrigeration.

Explanation:

Ozone layer prevents the harmful radiation from entering the earth's surface.

Ultraviolet radiation is very harmful radiation. Exposure of this radiation can cause Skin cancer. It is the main cause of the sunburn.

The depletion of the ozone layer is due to CFC (chloro fluoro carbon) which is widely used in air conditioner and refrigeration.

CFC is broken down by ultraviolet radiation. Then, the chlorine is released. This chlorine reacts with oxygen. In this way, it destroys the ozone molecule.

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A marble is dropped from rest and falls for 2.3 seconds. Find its final velocity.

juin [17]

Answer:

23 m/s downward

__________________________________________________________

Taking the downward direction as positive

We are given:

Initial velocity of the marble (u) = 0 m/s

Time interval (t) = 2.3 seconds

Final velocity (v) = x m/s

Solving for the Final velocity:

Acceleration of the Marble:

We know that gravity will make the marble accelerate at a constant acceleration of 10 m/s

Final velocity:

v = u + at [First equation of motion]

x = 0 + (10)(2.3) [replacing the given values]

x = 23 m/s

Hence, after 2.3 seconds, the marble will move at a velocity of 23 m/s in the downward direction

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3 years ago

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A car traveling at 22.4 m/s skids to a stop in 2.55s determine the skidding distance of the car ?

nlexa [21]

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3 years ago

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al aplicar una fuerza de 2 N sobre un muelle este se alarga 4cm.¿cuanto se alargara si la fuerza es el triple?¿que fuerza tendri

3241004551 [841]

1) 12 cm

2) 3 N

Explanation:

The relationship between force and elongation in a spring is given by Hooke's law:

$F=kx$

where

F is the force applied

k is the spring constant

x is the elongation

For the spring in this problem, at the beginning we have:

$F=2 N$

$x=4 cm$

So the spring constant is

$k=\frac{F}{x}=\frac{2N}{4 cm}=0.5 N/cm$

Later, the force is tripled, so the new force is

$F'=3F=3(2)=6 N$

Therefore, the new elongation is

$x'=\frac{F'}{k}=\frac{6}{0.5}=12 cm$

In this second problem, we know that the elongation of the spring now is

$x=6 cm$

From part a), we know that the spring constant is

$k=0.5 N/cm$

Therefore, we can use the following equation to find the force:

$F=kx$

And substituting k and x, we find:

$F=(0.5)(6)=3 N$

So, the force to produce an elongation of 6 cm must be 3 N.

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3 years ago