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On January 1, Year 1, Scott Company purchased a new machine for $220,000. The machine is expected to have an eight-year life and

dlinn [17]

Answer:

1. Annual straight-line depreciation = 25000

2. Machine's book value at the end of Year 2 = 170000

3. Gain on the sale of the machine = 10000

Step-by-step explanation:

1. Let's review the information provided to us to answer the questions correctly:

Price of the new machine purchased by Scott Company = 220,000

Expected life of the machine = 8 years

Salvage value = 20,000

Price of sale of the machine after 2 years of usage = 180,000

2. Calculate the annual straight-line depreciation on the machine.

Annual depreciation = (Price of purchase of the new machine - Salvage value)/Expected life of the machine

Replacing with the real values, we have:

Annual depreciation = (220,000 - 20,000)/8

Annual depreciation = 200,000/8

Annual straight-line depreciation = 25000

3. What is the machine's book value at the end of Year 2 after the annual depreciation has been recorded?

Machine's book value at the end of Year 2 = Price of the new machine purchased by Scott Company - 2 * Annual straight-line depreciation

Replacing with the real values, we have:

Machine's book value at the end of Year 2 = 220,000 - 2 * 25,000

Machine's book value at the end of Year 2 = 220,000 - 50,000

Machine's book value at the end of Year 2 = 170000

4. Calculate the gain or loss on the sale of the machine.

Gain or loss on the sale of the machine = Price of sale of the machine after 2 years of usage - Machine's book value at the end of Year 2

Replacing with the real values, we have:

Gain or loss on the sale of the machine = 180,000 - 170,000

Gain on the sale of the machine = 10000

8 0

3 years ago

Three rational numbers between 5/31 and 6/31

Ludmilka [50]

Answer:

$\dfrac{26}{155}$ , $\dfrac{27}{155}$ , and $\dfrac{28}{155}$ .

Step-by-step explanation:

What is a rational number? By definition, a rational number can be represented as the fraction of two integers.

The goal is to find three fractions in the form $\dfrac{p}{q}$ between $\dfrac{5}{31}$ and $\dfrac{6}{31}$ .

$\dfrac{5}{31} < \dfrac{p}{q} < \dfrac{6}{31}$ .

At this moment, there doesn't seems to be a number that could fit. The question is asking for three of these numbers. Multiple the numerator and the denominator by a number greater than three (e.g., five) to obtain

$\dfrac{25}{155} < \dfrac{p}{q} < \dfrac{30}{155}$ .

Since $p$ and $q$ can be any integers, let $q = 155$ .

$\dfrac{25}{155} < \dfrac{p}{155} < \dfrac{30}{155}$ .

$\implies 25 < p < 30$ .

Possible values of $p$ are 26, 27, and 28. That corresponds to the fractions

$\dfrac{26}{155}$ , $\dfrac{27}{155}$ , and $\dfrac{28}{155}$ .

These are all rational numbers for they are fractions of integers.

6 0

3 years ago

Which statement describes a situation that can be represented by an exponential function?

swat32

Answer: c

Step-by-step explanation:

5 0

3 years ago

People with bmi less than 18.5 are often classified as underweight. What percent of men aged 20-29 are underweight by this crite

Archy [21]

You need more information. If you had the bmi's of every man between 20 and 29 you could get an exact answer. If you had a good sample you could get a good estimate of this answer.

3 0

3 years ago

Aliya buys p pounds of apples for $2 per pounds. Write an algebraic expression to find the total cost?

Burka [1]

Answer:

Identify the terms and coefficients of each expression. 1. ... Frank buys p pounds of oranges for $2.29 per pound and the same number of pounds of apples for $1.69 per pound. ... .690 = total cost ... Write an expression to represent each situation. 9. Eliza earns $400 per week plus $15 for each new customer she signs up.

Step-by-step explanation:

3 0

2 years ago