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3 years ago

HELP ASAP!!

Mathematics

2 answers:

blondinia [14]3 years ago

7 0

Answer:

84 square inches

Step-by-step explanation:

First, separate this shape into two shapes you can easily find the area of. You can do this by turning it into a rectangle and a rhombus.

Say the rectangle has measurements of 5 by 6 inches. The area of that rectangle will be 30 square inches. Save this value to add on later.

The rhombus now has a height of 4 (because the side length 10 minus the side length 6 equals 4), and two bases by the values of 12 and 15. The area of a rhombus can be found with the equation:

a = 1/2(b1 + b2) x h

Simply plug in those values to find the area of the rhombus, 54. Now add the area of the rhombus and the area of the rectangle to get 84 square inches as your final area.

Monica [59]3 years ago

3 0

B because it makes sense

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A property sells for $140,000 two years after it was purchased. If the annual appreciation rate is 6%, how much did the original

kykrilka [37]

Answer:

$123,200

Step-by-step explanation:

0.06 x 2 = 0.12

140,000 x 0.12 = 16,800

140,000 - 16,800 = 123,200

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3 years ago

0.4 in fraction form. Please

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Answer:

4/10

Step-by-step explanation:

0.4 is said by "four-tenths." Fractions are also said the same way. Notice how there is a four and a ten. This should be easier to help you make decimals in fraction form. The four would be the numerator and the ten would be the denominator, making the final answer 4/10.

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4 years ago

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Joe borrowed $5,000 from the bank at a rate of 7% simple interest per year. How much interest did he pay in 7 years?

yaroslaw [1]

Answer:

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Step-by-step explanation:

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I hope this helps.

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3 years ago

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(A) A small business ships homemade candies to anywhere in the world. Suppose a random sample of 16 orders is selected and each

Leviafan [203]

Following are the solution parts for the given question:

For question A:

$\to (n) = 16$

$\to (\bar{X}) = 410$

$\to (\sigma) = 40$

In the given question, we calculate $90\%$ of the confidence interval for the mean weight of shipped homemade candies that can be calculated as follows:

$\to \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{S}{\sqrt{n}}$

$\to C.I= 0.90\\\\\to (\alpha) = 1 - 0.90 = 0.10\\\\ \to \frac{\alpha}{2} = \frac{0.10}{2} = 0.05\\\\ \to (df) = n-1 = 16-1 = 15\\\\$

Using the t table we calculate $t_{ \frac{\alpha}{2}} = 1.753$ When $90\%$ of the confidence interval:

$\to 410 \pm 1.753 \times \frac{40}{\sqrt{16}}\\\\ \to 410 \pm 17.53\\\\ \to392.47 < \mu < 427.53$

So $90\%$ confidence interval for the mean weight of shipped homemade candies is between $392.47\ \ and\ \ 427.53$ .

For question B:

$\to (n) = 500$

$\to (X) = 155$

$\to (p') = \frac{X}{n} = \frac{155}{500} = 0.31$

Here we need to calculate $90\%$ confidence interval for the true proportion of all college students who own a car which can be calculated as

$\to p' \pm Z_{\frac{\alpha}{2}} \times \sqrt{\frac{p'(1-p')}{n}}$

$\to C.I= 0.90$

$\to (\alpha) = 0.10$

$\to \frac{\alpha}{2} = 0.05$

Using the Z-table we found $Z_{\frac{\alpha}{2}} = 1.645$

therefore $90\%$ the confidence interval for the genuine proportion of college students who possess a car is

$\to 0.31 \pm 1.645\times \sqrt{\frac{0.31\times (1-0.31)}{500}}\\\\ \to 0.31 \pm 0.034\\\\ \to 0.276 < p < 0.344$

So $90\%$ the confidence interval for the genuine proportion of college students who possess a car is between $0.28 \ and\ 0.34.$

For question C:

In question A, We are $90\%$ certain that the weight of supplied homemade candies is between 392.47 grams and 427.53 grams.
In question B, We are $90\%$ positive that the true percentage of college students who possess a car is between 0.28 and 0.34.

Learn more about confidence intervals:

brainly.in/question/16329412

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3 years ago

Is the relation a function?<br> X Y

AveGali [126]

Answer:

yes

Step-by-step explanation:

there is a single x value for every y value

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3 years ago