Answer:
The average rate of change of rainfall in the rainforest between 2nd year and 6th year = <u>3 inches</u>
Step-by-step explanation:
Given function representing inches of rainfall:
To find the average rate of change between the 2nd year and the 6th year.
Solution:
The average rate of change between interval ![[a,b]](https://tex.z-dn.net/?f=%5Ba%2Cb%5D)
is given as :
For the given function we need to find the average rate of change between 2nd year and 6th year. ![[2,6]](https://tex.z-dn.net/?f=%5B2%2C6%5D)
So, we have:
Thus, average rate of change will be:
⇒ 
⇒ 
⇒ 
Thus, the average rate of change of rainfall in the rainforest between 2nd year and 6th year = 3 inches
Answer:
The answer is 16.8 cm^ 2.
Answer:
30
Step-by-step explanation:
We require to calculate the volume of 1 brick
V = lbh ( l is length, b is breadth and h is height ), that is
V = 14 × 8 × 5 = 560 cm³
Now divide the volume of concrete available by the volume of 1 brick.
number of bricks made = 
= 30
Answer: The answer is 381.85 feet.
Step-by-step explanation: Given that a window is 20 feet above the ground. From there, the angle of elevation to the top of a building across the street is 78°, and the angle of depression to the base of the same building is 15°. We are to calculate the height of the building across the street.
This situation is framed very nicely in the attached figure, where
BG = 20 feet, ∠AWB = 78°, ∠WAB = WBG = 15° and AH = height of the bulding across the street = ?
From the right-angled triangle WGB, we have
and from the right-angled triangle WAB, we have'
Therefore, AH = AB + BH = h + GB = 361.85+20 = 381.85 feet.
Thus, the height of the building across the street is 381.85 feet.
