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olga55 [171]
3 years ago
5

HELP I'M TIMED! Reflect triangle ABC over the y-axis. What is the relationship between the segments created if you connect the p

oints to the line of reflection. I WILL GIVE YOU BRAINLIEST!

Mathematics
2 answers:
mylen [45]3 years ago
5 0

Answer:

they are perpendicular to each other

Step-by-step explanation:

4vir4ik [10]3 years ago
3 0

This is your answer thanks!


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(2a^3 b^4) ^4= <br> What is the answer to this problem ?
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Step-by-step explanation:

Everything in the parenthesis to the 4th power.

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Given: PRST is a square
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Answer:

(1-\sqrt{2})a^2

Step-by-step explanation:

Consider irght triangle PRS. By the Pythagorean theorem,

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Thus,

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Consider isosceles triangle MSC. In this triangle

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The area of this triangle is

A_{MSC}=\dfrac{1}{2}MS\cdot MC=\dfrac{1}{2}\cdot (\sqrt{2}-1)a\cdot (\sqrt{2}-1)a=\dfrac{(\sqrt{2}-1)^2a^2}{2}=\dfrac{(3-2\sqrt{2})a^2}{2}

Consider right triangle PTS. The area of this triangle is

A_{PTS}=\dfrac{1}{2}PT\cdot TS=\dfrac{1}{2}a\cdot a=\dfrac{a^2}{2}

The area of the quadrilateral PMCT is the difference in area of triangles PTS and MSC:

A_{PMCT}=\dfrac{(3-2\sqrt{2})a^2}{2}-\dfrac{a^2}{2}=\dfrac{(2-2\sqrt{2})a^2}{2}=(1-\sqrt{2})a^2

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