Let's call this line y=mx+C, whereby 'm' will be its gradient and 'C' will be its constant.
If this line is parallel to the line you've just mentioned, it will have a gradient 2/3. We know this, because when we re-arrange the equation you've given us, we get...

So, at the moment, our parallel line looks like this...
y=(2/3)*x + C
However, you mentioned that this line passes through the point Q(1, -2). If this is the case, for the line (almost complete) above, when x=1, y=-2. With this information, we can figure out the constant of the line we want to find.
-2=(2/3)*(1) + C
Therefore:
C = - 2 - (2/3)
C = - 6/3 - 2/3
C = - 8/3
This means that the line you are looking for is:
y=(2/3)*x - (8/3)
Let's find out if this is truly the case with a handy graphing app... Well, it turns out that I'm correct.
Here let us first write the value of each number:
6 thousands means 6*1000=6000.
9 hundreds means 9*100=900.
12 tens means 12*10 =120
10 ones means 10*1 =10
3 tenths means 3/10 =0.3
Now we just have to add all these values to get the final number.
adding 6000 + 900 +120 +10 +0.3 = 7030.3
So the final number is 7030.3
It took her 29 minutes to race. :)
Answer:
303
Step-by-step explanation:
So the equation to find a term is An=a1+(n-1)d
An represents the value of the number (n)
and n is the selective that you want
d is the difference between the first and second term which is 23-18=5, and you can see that adding 5 to the previous term gives the following term.
a1 is the first term in the sequence
so knowing all that now you can go back and inset all variables into the equation
An=18+(58-1)5
An=303
Hope that helps :)
Please give brainliest