Look at image i need help

Katie has 4 grape candies and 3 cherry candies. The ratio of the mumber of grape candies to the total number of candies is what?

dimaraw [331]

Answer 4:7

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Chris is standing on a cliff that is 3 feet above sea level. He dives into the water and descends to a depth 10 feet below the s

Gnoma [55]

13
Use a number line to help.

5 0

3 years ago

Write an equivalent expression for the 4th root of 324m^12 * the cubed root of 64k^9. Need help!

Elis [28]

Answer:

The equivalent expression to the givan expression is

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}=12\sqrt[4]{4}m^3k^3$

Step-by-step explanation:

Given expression is 4th root of 324m^12 * the cubed root of 64k^9

The given expression can be written as

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}$

To find the equivalent expression to the given expression :

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}$

$=\sqrt[4]{81\times 4m^{12}}\times\sqrt[3]{16\times 4k^9}$

$=\sqrt[4]{3\times 3\times 3\times 3\times 4m^{12}}\times\sqrt[3]{4\times 4\times 4k^9}$

$=(3\times \sqrt[4]{m^{12}})\times (4\times \sqrt[3]{k^9})$

$=(3\times \sqrt[4]{4m^{12}})\times (4\times \sqrt[3]{k^9})$

$=(3\times \sqrt[4]{4}\times (m^{12})^{\frac{1}{4}})\times (4\times {(k^9)^{\frac{1}{3}})$

$=(3\sqrt[4]{4}\times m^{\frac{12}{4}})\times (4\times k^{\frac{9}{3}})$

$=(3\sqrt[4]{4}\times m^3)\times (4\times k^3)$

$=3\sqrt[4]{4}m^3.4k^3$

$=12\sqrt[4]{4}m^3k^3$

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}=12\sqrt[4]{4}m^3k^3$

Therefore the equivalent expression to the given expression is

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}=12\sqrt[4]{4}m^3k^3$

8 0

3 years ago

In a recipe, for every tablespoon of sugar there are four teaspoons of salt. If a batch uses twelve tablespoons of sugar, how ma

marysya [2.9K]

4*12= 48
The answer is 48

3 0

3 years ago

Solve the question in the picture and write the correct answer

zlopas [31]

Answer:

36.24 cm²

Step-by-step explanation:

The shaded region is the inscribed circle in the isosceles triangle. In order to find its area, we need to know the radius of the circle.

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One way to find the radius of the circle is to make use of the Angle Bisector theorem. It tells us an angle bisector divides the sides of a triangle proportionately. In the attached figure, that means angle bisector CD divides segment AE in proportion to sides CA and CE.

<h3>Side Length</h3>

To make use of this theorem, we need to know the length of side CA. That is the hypotenuse of right triangle AEC, so can be found using the Pythagorean theorem. Isosceles triangle ABC is given as having height AE=10 and base BC = 12.

CA² = CE² +AE²

CA² = 6² +10² = 136 . . . . . . . CE is half the base length: 12/2 = 6

CA = √136 = 2√34

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<h3>Radius</h3>

Now we can write the proportion using the angle bisector theorem.

DE/CE = DA/CA

r/6 = (10 -r)/(2√34)

r√34 = 3(10 -r) . . . . . . . multiply by 6√34

r(3 +√34) = 30

r = 30/(3 +√34)

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From this, we can find the area of the shaded circle to be ...

A = πr² = (3.14)(30/(3 +√34))²

= 3.14·900/(43 +6√34) ≈ 36.2374 . . . cm²

The area of the shaded region is about 36.24 cm².

_____

<em>Additional comment</em>

Using area considerations, the formula for the radius of the inscribed circle in an isosceles triangle with base 'b' and sides 'a' can be found to be ...

$r=\dfrac{b}{2}\sqrt{\dfrac{2a-b}{2a+b}}$

For a=√136 and b=12, this becomes ...

$r=\dfrac{12}{2}\sqrt{\dfrac{2\sqrt{136}-12}{2\sqrt{136}+12}}=6\sqrt{\dfrac{(\sqrt{34}-3)^2}{34-9}}=1.2(\sqrt{34}-3)\approx3.39714$

This is the same value we found above.

3 0

2 years ago