PLS HELP If |7 − 6y| > 30, whats the possible value of y?
1 answer:
Answer:
y<−23/6 or y> 37/6
Step-by-step explanation:
Solve Absolute Value.
|−6y+7|>30
We know either−6y+7>30or−6y+7<−30
−6y+7>30(Possibility 1)
−6y+7−7>30−7(Subtract 7 from both sides)
−6y>23
−6y
/−6 > 23/−6
(Divide both sides by -6)
y<−23/6
−6y+7<−30(Possibility 2)
−6y+7−7<−30−7(Subtract 7 from both sides)
−6y<−37
−6y/−6< −37/−6
(Divide both sides by -6)
y> 37/6
Therefore the answer is
y<−23/6 or y> 37/6
I hope this helped you.
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