Answer:
x=0
Step-by-step explanation:
We are given:
g(x) =10x +2
and
g(x)=2
g(x) is equal to both 10x+2 and 2. Therefore, by substitution, we can set them equal to each other
10x+2=2
Now, we need to solve for x. First, move all the numbers to the same side. Subtract 2 from both sides
10x+2-2=2-2
10x=0
To solve for x, we have to get x by itself. x and 10 are being multiplied. To get x alone, divide both sides by 10.
10x/10=0/10
x=0
You multiply the length of the model car by the meters from the actual car. It’s easier to convert one unit of measurement to match with the other. I found it easier to convert 18.2 cm to meters which is 0.182 m. Now we multiply 0.182m by 0.3m to get the length of the actual car.
The answer would be 0.0546m. Or if you prefer centimeters, then the answer would be 5.46 cm. Either way is fine.
Hope this helped, please let me know if I was correct. :D
The hourly rate is 60, so multiply 60 by the number of hours (h) and add the fee:
Answer: 60h + 35
Step-by-step explanation:
Hey there!
<u>Use</u><u> </u><u>cos</u><u> </u><u>ratio to</u><u> </u><u>find </u><u>the</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>'</u><u>a'</u><u>.</u>
As per given, we can state that it is a Right angled triangle, so taking 38° reference angle.
We get;
p = AC
b = 6
and h= a
Here, <u>Use</u><u> </u><u>the</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>b</u><u>,</u><u> </u><u>h</u><u> </u><u>and</u><u> </u><u>3</u><u>8</u><u>°</u><u> </u><u>angle</u><u> </u><u>to</u><u> </u><u>find</u><u> </u><u>the</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>a</u><u>.</u>
[ cos(38°=0.7881]
Therefore the measure of a is 7.61 Or 8.
<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
a rectangle is twice as long as it is wide . if both its dimensions are increased 4 m , its area is increaed by 88 m squared make a sketch and find its original dimensions of the original rectangle
Step-by-step explanation:
Let l = the original length of the original rectangle
Let w = the original width of the original rectangle
From the description of the problem, we can construct the following two equations
l=2*w (Equation #1)
(l+4)*(w+4)=l*w+88 (Equation #2)
Substitute equation #1 into equation #2
(2w+4)*(w+4)=(2w*w)+88
2w^2+4w+8w+16=2w^2+88
collect like terms on the same side of the equation
2w^2+2w^2 +12w+16-88=0
4w^2+12w-72=0
Since 4 is afactor of each term, divide both sides of the equation by 4
w^2+3w-18=0
The quadratic equation can be factored into (w+6)*(w-3)=0
Therefore w=-6 or w=3
w=-6 can be rejected because the length of a rectangle can't be negative so
w=3 and from equation #1 l=2*w=2*3=6
I hope that this helps. The difficult part of the problem probably was to construct equation #1 and to factor the equation after performing all of the arithmetic operations.