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11111nata11111 [884]
3 years ago
13

PLEASE EXPLAIN!

Mathematics
1 answer:
stepladder [879]3 years ago
6 0

Answer:

15

Step-by-step explanation:

5(2)(3)-2(2)+13+7(2)-6(2)(3)-4(2)+(2)(3)

30-4+13+14-36-8+6

15

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Can someone help me find x
Viefleur [7K]

Answer:

Rounded to the nearest tenth: x=5.7 in

Rounded to the nearest hundredth: x=5.74 in

Step-by-step explanation:

We have a right triangle with a given angle of 35°. We also have the opposite side of that angle, x, and its hypotenuse 10 in. To find x, we are using the trig function that relates  the opposite side with the hypotenuse; in other words, the sine trig function.

sin\alpha =\frac{opposite}{hypotenuse}

sin(35)=\frac{x}{10}

x=10sin(35)

x=5.735764364

Rounded to the nearest tenth: x=5.7 in

Rounded to the nearest hundredth: x=5.74 in

4 0
3 years ago
Solve the system of equation <br> y=4x-3<br> Y=-2x+9
Anna [14]
Y=4x-3=1
Y=-2x+9=11 that’s the answer
5 0
2 years ago
20. In the figure at right, ABDC lies in plane k and AD IDC.
Citrus2011 [14]

The option that's true about the plane illustrated is E. None of these.

<h3>How to illustrate the plane?</h3>

From the information given, it should be noted that DBC isn't an isosceles triangle.

Also, from the figure, one can see that DAB isn't similar to DAC.

Likewise, BD and DC aren't perpendicular.

In conclusion, the correct option is E.

Learn more about plane on:

brainly.com/question/2251564

#SPJ1

4 0
2 years ago
the city park department is planning to enclose a play aea. one side of the area will be against an existing building, so no fen
SVEN [57.7K]

Answer:

length = 200 m

width = 400 m

Step-by-step explanation:

Let the length of the plaing area is L and the width of the playing area is W.

Length of fencing around three sides = 2 L + W = 800

W = 800 - 2L ..... (1)

Let A is the area of playing area

A = L x W

A = L (800 - 2L)

A = 800 L - 2L²

Differentiate with respect to L.

dA/dL = 800 - 4 L

It is equal to zero for maxima and minima

800 - 4 L = 0

L = 200 m

W = 800 - 2 x 200 = 400 m

So, the area is maximum if the length is 200 m and the width is 400 m.

8 0
3 years ago
Read 2 more answers
4=2(c-6)-4 solve for c
Naddik [55]
4=2c-12-4
4=2c-16
20=2c
10=c
8 0
3 years ago
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