Please help me with this math problem (image below)

Mathematics

1 answer:

VashaNatasha [74]2 years ago

6 0

Answer:

Option B.

Step-by-step explanation:

Obvious. Lets explain:

Option A: It's pretty ease to do. You just need 2 triangles to make a parallelogram, and that's that.

Option B: How can you make a rectangle from triangles-???

Option C: You might think I am wrong, but I am right. Get 6 triangles, then plato, you have a whole hexagon!

Option D: You probably already know this...but you just need three triangles.

It's correct on every school thing.

<h2>Option B is your answer!</h2>

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Assuming x > 0, which of these expressions is equivalent to 11 times the square root of 245 x to the third plus 9 times the s

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11 times the square root of 245 x to the third plus 9 times the square root of 45 x to the third is:
 $11 \sqrt{245 x^{3} } +9 \sqrt{45 x^{3} } =11 \sqrt{245} *\sqrt{ x^{3} } +9 \sqrt{45} *\sqrt{ x^{3} }= \\ \\ =11 \sqrt{5*49} * \sqrt{ x^{2} *x} +9 \sqrt{5*9} * \sqrt{ x^{2} *x}= \\ \\ =11* \sqrt{5} * \sqrt{49} * \sqrt{ x^{2}} * \sqrt{x} +9* \sqrt{5} * \sqrt{9} * \sqrt{ x^{2} }* \sqrt{x} = \\ \\ 
=11* \sqrt{5} *7*x* \sqrt{x} +9* \sqrt{5} *3*x* \sqrt{x} = \\ \\ 
=77x* \sqrt{5*x} +27x* \sqrt{5*x} = \\ \\ 
=77x \sqrt{5x} +27x \sqrt{5x} = \\ \\ 
=104x \sqrt{5x}$

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3 years ago

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