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Irina18 [472]
3 years ago
12

How do i get the factor of 3p2-2p-5

Mathematics
2 answers:
tensa zangetsu [6.8K]3 years ago
5 0
3p² - 2p - 5 = 0

3p² + 3p - 5p - 5 = 0

3p(p + 1) -5(p + 1) = 0

(3p - 5)(p + 1) = 0

p = 5/3 or -1

Hope this helps!
Reika [66]3 years ago
5 0

The first term is, <span> <span>3p2</span> </span> its coefficient is <span> 3 </span>.
The middle term is, <span> -2p </span> its coefficient is <span> -2 </span>.
The last term, "the constant", is <span> -5 </span>

Step-1 : Multiply the coefficient of the first term by the constant <span> <span> 3</span> • -5 = -15</span> 

Step-2 : Find two factors of  -15  whose sum equals the coefficient of the middle term, which is  <span> -2 </span>.

<span><span>     -15   +   1   =   -14</span><span>     -5   +   3   =   -2   That's it</span></span>


Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -5  and  3 
                     <span>3p2 - 5p</span> + 3p - 5

Step-4 : Add up the first 2 terms, pulling out like factors :
                    p • (3p-5)
              Add up the last 2 terms, pulling out common factors :
                     1 • (3p-5)
Step-5 : Add up the four terms of step 4 :
                    (p+1)  •  (3p-5)
             Which is the desired factorization

Final result : (3p - 5) • (p + 1) <span>
</span>
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