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nadezda [96]
3 years ago
11

Agree or disagree

Physics
1 answer:
OLga [1]3 years ago
4 0
Agree cause it is that persons environment not the law or the law makers
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Cavendish used the attraction between large and small lead balls to measure an experimental value for the gravitational constant
irina1246 [14]

The gravitational constant was experimentally measured by W Cavendish using the attraction between big and small lead balls. is true

The correct answer is true

<h3>How do you define gravitational constant?</h3>

the strength of gravity. a factor in use in Newton's gravity law to relate the strength of the gravitational pull between two bodies with their masses and distance from one another. 6.67259 X 10-11 newtons per square kilogram is roughly the gravitational constant. G is its identifier.

<h3> where is the strongest gravity is?</h3>

The gravitational pull of the earth is greatest near sea level, normally, and weakens as you get further from the center, such as to the summit of Mt. Everest. Because the obloid earth was slightly wider, but only by a minor ratio, the gravity just at poles is stronger than that at the equator.

To know more about gravitational constant visit:

brainly.com/question/858421
#SPJ9

8 0
10 months ago
In a hydraulic lift, the radius of the small and large pistons are
Gennadij [26K]

Answer:

the answer is 52.15cm×35.5

8 0
2 years ago
What is the thermal efficiency of a gas power cycle using thermal energy reservoirs at 627°C and 90°C?
vlada-n [284]

Answer:

The value is \eta = 63\%

Explanation:

Generally the thermal efficiency is mathematically represented as

\eta =  1 -  \frac{T_L}{T_H} * 100

substituting  [ 627°C + 273  =  900K ]  for  T_H and    [ 90°C + 273  =  333K ]  for T_L

   So  

         \eta =  1 -  \frac{333}{900} *100

=>     \eta = 63\%

5 0
3 years ago
A person takes a trip, driving with a constant speed of 89.5km/h, except for a 22.0−min rest stop. If the person's average speed
Elanso [62]

Answer:

stop using brainly and learn this bs in class

Explanation:

8 0
3 years ago
In the year 2055, a rocket was launched from a research laboratory on Mars. Mars has essentially no atmosphere. The test rocket
algol [13]

Answer:

h = 618.64 m

Explanation:

First we need to calculate the height gained by rocket while the fuel is burning. We use 2nd equation of motion for that purpose:

h₁ = Vit + (1/2)at²

where,

h₁ = height gained during the burning of fuel

Vi = Initial Velocity = 0 m/s

t = time = 7 s

a = acceleration = 8 m/s²

Therefore,

h₁ = (0 m/s)(7 s) + (1/2)(8 m/s²)(7 s)²

h₁ = 196 m

Now we use 1st equation of motion to find final speed Vf:

Vf = Vi + at

Vf = 0 m/s + (8 m/s²)(7 s)

Vf =  56 m/s

Now, we calculate height covered in free fall motion. Using 3rd equation of motion:

2ah₂ = Vf² - Vi²

where,

a = - 3.71 m/s²

h₂ = height gained during free fall motion = ?

Vf = Final Velocity = 0 m/s (since, rocket will stop at highest point)

Vi = 56 m/s

Therefore,

(2)(-3.71 m/s²)h₂ = (0 m/s)² - (56 m/s)²

h₂ = 422.64 m

So the total height gained will be:

h = h₁ + h₂

h = 196 m + 422.64 m

<u>h = 618.64 m</u>

4 0
2 years ago
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