The answer for this problem is explained through this, the system is absorbing (+). And now see that it uses that the SURROUNDINGS are doing 84 KJ of work. Anytime a system is consuming work done on it by the surroundings the sign will be +. So it's just 159 KJ + 84 = 243 KJ.
Pick which "black" box goes with each rock....
...ex- the bottom right can be in the sedimentary rock...box
Answer:
A) t = 29.3 s
B) V = 58.56 ft/s
C) a_net = 2.3 ft/s²
Explanation:
A) The formula for radial acceleration is given as;
a_c = V²/R
We are given;
Radius;R = 350 ft
So, a_c = V²/350
Where V is velocity
Tangential acceleration;a_t = 2 ft/s²
Formula for net acceleration is;
a_net = √((a_c)² + (a_t)²)
We are given a_net = 10 ft/s²
Thus;
10 = √(V²/350)² + (2²)
10² = V⁴/350² + 4
100 - 4 = V⁴/350²
96 × 350² = V⁴
V = 58.56 ft/s
Now, formula for angular velocity is;
ω = V/r
ω = 58.56/350
ω = 0.1673 rad/s
Angular acceleration is given by;
α = a_t/r
α = 2/350
α = 0.00571 rad/s²
Time needed will be gotten from the formula;
t = ω/α
t = 0.1673/0.00571
t = 29.3 s
B) we are told total acceleration is 10 ft/s², thus it's the same as velocity gotten earlier which is 58.56 ft/s
C) we are told that the speed is now 20 ft/s
Thus;
a_c = 20²/350
a_c = 1.1429 ft/s²
Since a_net = √((a_c)² + (a_t)²)
We are given a_t = 2 ft/s²
Thua;
a_net = √(1.1429² + 2²)
a_net = √5.30622041
a_net = 2.3 ft/s²
The object with the greater mass has a greater gravitational force and that determines what satellites orbit around it. An object with more mass will never orbit an object with less.
Since the car is at rest, the force experienced by car will be normal face(exerted by surface to which car is in contact) and weight of the car.
As the car is at rest, net force on the car should be zero.