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Paraphin [41]
3 years ago
14

2 Calculate the distance from a srtaight wire where the magnetuc field is 0.66 T. the current in the wire is 4A and K = 2 x 10^-

7. [
Physics
1 answer:
nirvana33 [79]3 years ago
7 0

Answer:I don't know!!!!I don't know!!!!I don't know!!!!I don't know!!!!I don't know!!!!

Explanation:

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A ball is thrown upward. what can be said about the system ?
Liula [17]
That you have thrown a ball with kinetic energy upwards at an increasing velocity rate
4 0
3 years ago
Read 2 more answers
Please help!
julsineya [31]

Answer:

Answer:

3 g/cm          

Explanation:

Mass of stone = 30 g

Initial volume of cylinder = 50 cm

Increased volume = 60 cm

Volume = 60-50

= 10 cm

Density of stone = Mass/Volume

= 30/10

= 3 g/ml            as 1 ml = 1 cm

= 3 g/ml          

Explanation:

6 0
3 years ago
Which vector is the sum of vectors a and ?<br> b<br> а<br> O<br> A.<br> B.<br> C.
seropon [69]

Answer:

i would say D.

Explanation:

5 0
3 years ago
The law of conservation of momentum states that the total momentum of interacting objects does not change . This means the total
pickupchik [31]

Answer:

The momentum of an object is equal to the product of its mass and its velocity.

Explanation:

Consider an object of mass m travelling at a velocity \vec{v}. The momentum \vec{p} of this object would be:

\vec{p} = m \cdot \vec{v}.

For the law of conservation of momentum, consider two objects: object \rm a and object \rm b. Assume that these two objects collided with each other.

  • Let m_{\rm a} and m_{\rm b} denote the mass of the two objects.
  • Let \vec{v}_{\rm a}(\text{initial}) and \vec{v}_{\rm b}(\text{initial}) denote the velocity of the two object right before the interaction.
  • Let \vec{v}_{\rm a}(\text{final}) and \vec{v}_{\rm b}(\text{final}) denote the velocity of the two objects right after the interaction.
  • The momentum of the two objects right before the collision would be m_{\rm a}\cdot \vec{v}_{\rm a}(\text{initial}) and m_{\rm b}\cdot \vec{v}_{\rm b}(\text{initial}), respectively.
  • The momentum of the two objects right after the collision would be m_{\rm a}\cdot \vec{v}_{\rm a}(\text{final}) and m_{\rm b}\cdot \vec{v}_{\rm b}(\text{final}), respectively.

The sum of the momentum of the two objects would be:

  • m_{\rm a}\cdot \vec{v}_{\rm a}(\text{initial}) + m_{\rm b}\cdot \vec{v}_{\rm b}(\text{initial}) right before the collision, and
  • m_{\rm a}\cdot \vec{v}_{\rm a}(\text{final}) + m_{\rm b}\cdot \vec{v}_{\rm b}(\text{final}) right after the collision.

Assume that the system of these two objects is isolated. By the law of conservation of momentum, the sum of the momentum of these two objects should be the same before and after the collision. That is:

m_{\rm a}\cdot \vec{v}_{\rm a}(\text{initial}) + m_{\rm b}\cdot \vec{v}_{\rm b}(\text{initial}) = m_{\rm a}\cdot \vec{v}_{\rm a}(\text{final}) + m_{\rm b}\cdot \vec{v}_{\rm b}(\text{final}).

4 0
4 years ago
Which is the amount of matter in an object? a. weight b.mass c.volume d.pounds ​
hodyreva [135]

Answer:

(1.) (A.) wight

Explanation:

8 0
3 years ago
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