Answer:
The acceleration is 2 m/s2.
Explanation:
We calculate the acceleration (a), with the data of mass (m) and force (F), through the formula:
F = m x a ---> a= F/m
a = 40 N/20 kg <em> 1N= 1 kg x m/s2</em>
a= 40 kgx m/s2/ 20 kg
<em>a= 2 m/s2</em>
Answer:
I=0.0361 kg.m^2
Explanation:
Torque is the rotational equivalent of a force
Torque= perpendicular distance r X Force F
Torque T = I(moment of inertia) X α (angular acceleration)
T= Iα
r= 0.0285m
F= 1.9 x 10^3
T=0.0285 x 1.9 x 10^3
T= 54.15Nm
I=T/α
I=54.15/150
I=0.361 kg.m^2
Answer:
The change in momentum is
Explanation:
From the question we are told that
The mass of the probe is ![m = 170 kg](https://tex.z-dn.net/?f=m%20%3D%20170%20kg)
The location of the prob at time t = 22.9 s is ![A =](https://tex.z-dn.net/?f=A%20%20%3D%20%3C5600%2C%207200%2C0%3E)
The momentum at time t = 22.9 s is
The net force on the probe is ![F = N](https://tex.z-dn.net/?f=F%20%3D%20%3C-4000%20%2C%20-780%20%2C%200%3E%20N)
Generally the change in momentum is mathematically represented as
![\Delta p = F * \Delta t](https://tex.z-dn.net/?f=%5CDelta%20p%20%3D%20F%20%2A%20%5CDelta%20t)
The initial time is 22.6 s
The final time is 22.9 s
Substituting values
![\Delta p = * (22.9 - 22.6)](https://tex.z-dn.net/?f=%5CDelta%20p%20%3D%20%3C-4000%20%2C%20-780%20%2C%200%3E%20%2A%20%2822.9%20-%2022.6%29)
Answer: equation for the reaction is given below
PCL2+PCL3=PCL5
Where pcl2=0.40atm,pcl3=0.27atm
Pcl5=0.0029atm
Using ∆G=-RTin(PCL5/PCl2*PCL3)
Where R=8.314J/K/mol and T=298K
∆G=-8.314*298in(0.0029/0.40*.27)
∆G=8962.6J/mol
Explanation:
Crates is the correct answer because they create dents that make the bumps of mountains.