A bullet with a mass of 0.04-kg is traveling horizontally at 1400 m/s when it strikes a stationary target that is balanced on th

Question

2 years ago

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A bullet with a mass of 0.04-kg is traveling horizontally at 1400 m/s when it strikes a stationary target that is balanced on th

e top of a wooden post. The target has a mass of 9.96-kg. The target, with the bullet embedded, is knocked off of the post and moves to the right. How fast is the target with the bullet lodged in it traveling?

Physics

1 answer:

hammer [34] · Answer 1 · 2023-01-04T16:43:17+03:00

The speed of the target with the bullet lodged in it is 5.6 m/s.

<h3>What is speed?</h3>

This is the rate of change of distance.

To calculate the speed of the target and the bullet lodged, we use the formula below.

Formula:

V = mu/(m+M)............. Equation 1

Where:

V = Speed of the target and the bullet
m = mass of the bullet
M = mass of the target
u = Initial speed of the target

From the question,

Given:

m = 0.04 kg
u = 1400 m/s
M = 9.96 kg

Substitute these values into equation 1

V = (0.04×1400)/(0.04+9.96)
V = 56/10
V = 5.6 m/s

Hence, the speed of the target with the bullet lodged in it is 5.6 m/s.

Learn more about speed here: brainly.com/question/6504879

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