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lesantik [10]
2 years ago
12

A bullet with a mass of 0.04-kg is traveling horizontally at 1400 m/s when it strikes a stationary target that is balanced on th

e top of a wooden post. The target has a mass of 9.96-kg. The target, with the bullet embedded, is knocked off of the post and moves to the right. How fast is the target with the bullet lodged in it traveling?
Physics
1 answer:
hammer [34]2 years ago
4 0

The speed of the target with the bullet lodged in it is 5.6 m/s.

<h3>What is speed?</h3>

This is the rate of change of distance.

To calculate the speed of the target and the bullet lodged, we use the formula below.

Formula:

  • V = mu/(m+M)............. Equation 1

Where:

  • V = Speed of the target and the bullet
  • m = mass of the bullet
  • M = mass of the target
  • u = Initial speed of the target

From the question,

Given:

  • m = 0.04 kg
  • u = 1400 m/s
  • M = 9.96 kg

Substitute these values into equation 1

  • V = (0.04×1400)/(0.04+9.96)
  • V = 56/10
  • V = 5.6 m/s

Hence, the speed of the target with the bullet lodged in it is 5.6 m/s.

Learn more about speed here: brainly.com/question/6504879

#SPJ1

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Which type wire should be used to increase resistance
8_murik_8 [283]

Nichrome wire. That's the stuff that toasters are made from. The resistance is pretty high, considering the diameter. 1 meter is at about the same guage as that listed below for copper is about 96 ohms.

Most of the time you are trying to use wire with the least resistance.

A meter of copper has a listed resistance of 0.024 ohms / meter. The wire is a 19 guage wire which makes it pretty thin.

===============

I'm not sure what you are asking. If want the resistance of something in terms of what would increase the resistance of the same material for both calculations then

Rule 1: It you decrease the wire diameter, you increase the resistance

Rule 2: If you increase the length of the wire, you increase the resistance.

Both rules assume you are using something like copper.

7 0
3 years ago
Read 2 more answers
A wheel moves in the xy plane in such a way that the location of its center is given by the equations xo = 12t3 and yo = R = 2,
Stella [2.4K]

Answer:

the velocity of the point P located on the horizontal diameter of the wheel at t = 1.4 s  is   P =  104.04 \hat{i} -314.432 \hat{j}

Explanation:

The free-body  diagram below shows the interpretation of the question; from the diagram , the wheel that is rolling in a clockwise directio will have two velocities at point P;

  • the peripheral velocity that is directed downward (-V_y) along the y-axis
  • the linear velocity (V_x) that is directed along the x-axis

Now;

V_x = \frac{d}{dt}(12t^3+2) = 36 t^2

V_x = 36(1.7)^2\\\\V_x = 104.04\ ft/s

Also,

-V_y = R* \omega

where \omega(angular velocity) = \frac{d\theta}{dt} = \frac{d}{dt}(8t^4)

-V_y = 2*32t^3)\\\\\\-V_y = 2*32(1.7^3)\\\\-V_y = 314.432 \ ft/s

∴ the velocity of the point P located on the horizontal diameter of the wheel at t = 1.4 s  is   P =  104.04 \hat{i} -314.432 \hat{j}

3 0
3 years ago
Any ss2 here (11th Grade)
Sever21 [200]

Answer:

<h2>a) 50°</h2><h2>b) 40°</h2>

Explanation:

Check the complete diagram n the attachment below

a) The angle of incidence on a plane surface is the angle between the incidence ray and the normal ray acting on a plane surface. The normal ray is the ray perpendicular to the surface while the incidence ray is the ray striking a plane surface.

According to the diagram, the angle of reflection r₂ on M₂ is 90°-g where g is the angle of glance.

Given angle of glance on M₂ to be 40°, r₂ = 90-40 = 50°

According the second law of reflection, the angle of incidence = angle of reflection, therefore i₂ = r₂ = 50° (on M₂)

Also ∠OO₂O₁ =  ∠OO₁O₂ = 40° (angle of glance on M₁){alternate angle}

The angle of incidence on M₁ = 90° - 40° = 50°

b) The angle of incidence to the surface of M₁(∠PO₁A)will be the angle of glance on M₁ which is equivalent to 40°

6 0
3 years ago
1. A car travels 36 miles North and then 45 miles East. How far does it
salantis [7]

Answer:

Explanation:

Displacement is the shortest distance or path between two points.

1) Displacement = √(36² + 45²) = 57.63 miles

2) Displacement = √(100² + 500²) = 509.9 meters

3) Displacement = √(60² + 40²) = 72.11 miles

4) Displacement = √(700² + 500²) = 860.23 miles

5) Displacement = 300 - 300 = 0 miles

6) Displacement = 200 + 100 = 300 miles

7) Displacement = √(650² + 650²) = 919.24 miles

8) Yes, since a distance is moved in a direction

6 0
3 years ago
One litre of crude oil weighs 9.6N. Calculate its specific weight, density and specific gravity.​
Zepler [3.9K]

Answer:

The answer is "\bold{9600 \frac{N}{m^3}, 978.59 \frac{kg}{m^3}, and \ 0.978}"

Explanation:

Given:

\to v=1\ liter= 10^{-3} \ m^3\\\\\to  w= 9.6 \ N\\

calculation:

Specific \ weight =\frac{w}{v}=\frac{9.6}{10^{-3}}=9600 \frac{N}{m^3} \\\\w=mg\\\\m= \frac{w}{g}=\frac{9.6}{9.81}=0.9785\ kg\\\\\rho\ (density)=\frac{m}{v}=\frac{0.9785}{10^{-3}}=978.59 \frac{kg}{m^3}\\\\specific \ gravity = \frac{\prho \ obj}{\rho w}=\frac{978.54}{1000}=0.978

4 0
2 years ago
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