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inna [77]
3 years ago
7

the point (3, 6/5) lies ln the graph representing a proportional relationship. Which of the following points also lie on the sam

e graph? select all that apply. A. (1, 0.4) B. (1.5, 6/10) C. (6/5, 3) D. (4, 11/5). E. (15, 6).
Mathematics
2 answers:
Tcecarenko [31]3 years ago
8 0
A B and E all fall on the line expressed.
fenix001 [56]3 years ago
4 0

Answer:

<h2>A, B, and D.</h2>

Step-by-step explanation:

According to the problem, the point (3, 6/5) represents a proportional relationship. To find the ratio of such proportion, we just need to divide the vertical coordinate by the horizontal coordinate as follows

r=\frac{y}{x}=\frac{\frac{6}{5} }{3}=\frac{6}{15}=0.4

The ratio of the proportion is 0.4. Now, we just need to find which point has the same ratio.

<h3>A.</h3>

r=\frac{0.4}{1}=0.4

This means that point A lies on the graph because it has the same ratio.

<h3>B.</h3>

r=\frac{\frac{6}{10} }{1.5}=\frac{0.6}{1.5}=0.4

Point B also lies on the graph.

<h3>C.</h3>

r=\frac{3}{\frac{6}{5} }=\frac{15}{6}=2.5

Point C doesn't lie on the graph because it doesn't have the same ratio.

<h3>D.</h3>

r=\frac{6}{15}=0.4

Point D lies in the graph.

Therefore, all points that also lie on the same graph are A, B and D, because all of them are in the same proportion.

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Please explain steps
vovikov84 [41]

Answer:

b.

Step-by-step explanation:

you keep the hole number. times the exponent 's. since one of them are negative it will be a fraction.

7 0
3 years ago
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A garden is shaped in the form of a regular heptagon (seven-sided), MNSRQPO. A circle with center T and radius 25m circumscribes
Alenkinab [10]

The relationship between the sides MN, MS, and MQ in the given regular heptagon is \dfrac{1}{MN} = \dfrac{1}{MS} + \dfrac{1}{MQ}

The area to be planted with flowers is approximately <u>923.558 m²</u>

The reason the above value is correct is as follows;

The known parameters of the garden are;

The radius of the circle that circumscribes the heptagon, r = 25 m

The area left for the children playground = ΔMSQ

Required;

The area of the garden planted with flowers

Solution:

The area of an heptagon, is;

A = \dfrac{7}{4} \cdot a^2 \cdot  cot \left (\dfrac{180 ^{\circ}}{7} \right )

The interior angle of an heptagon = 128.571°

The length of a side, S, is given as follows;

\dfrac{s}{sin(180 - 128.571)} = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)}

s = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)} \times sin(180 - 128.571) \approx 21.69

The \ apothem \ a = 25 \times sin \left ( \dfrac{128.571}{2} \right) \approx 22.52

The area of the heptagon MNSRQPO is therefore;

A = \dfrac{7}{4} \times 22.52^2 \times cot \left (\dfrac{180 ^{\circ}}{7} \right ) \approx 1,842.94

MS = \sqrt{(21.69^2 + 21.69^2 - 2 \times  21.69 \times21.69\times cos(128.571^{\circ})) \approx 43.08

By sine rule, we have

\dfrac{21.69}{sin(\angle NSM)} = \dfrac{43.08}{sin(128.571 ^{\circ})}

sin(\angle NSM) =\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ})

\angle NSM = arcsin \left(\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ}) \right) \approx 23.18^{\circ}

∠MSQ = 128.571 - 2*23.18 = 82.211

The area of triangle, MSQ, is given as follows;

Area \ of \Delta MSQ = \dfrac{1}{2}  \times  43.08^2 \times sin(82.211^{\circ}) \approx 919.382^{\circ}

The area of the of the garden plated with flowers, A_{req}, is given as follows;

A_{req} = Area of heptagon MNSRQPO - Area of triangle ΔMSQ

Therefore;

A_{req}= 1,842.94 - 919.382 ≈ 923.558

The area of the of the garden plated with flowers, A_{req} ≈ <u>923.558 m²</u>

Learn more about figures circumscribed by a circle here:

brainly.com/question/16478185

6 0
3 years ago
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Afina-wow [57]

Answer:

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Step-by-step explanation:

To write an equation in standard form, you want to arrange the terms from increasing to decreasing powers/exponents.

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First, lets arrange like terms together. Put the terms with the same exponent together.

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Now combine the terms with the same exponent by subtracting 5x³ from 2x³.

-3x³ + 4x² - 6x⁶ + 12 + 4x⁴

Now let's arrange the terms from increasing to decreasing powers/exponents.

-6x⁶ + 4x⁴ - 3x³ + 4x² + 12

This is your equation in standard form.

Hope this helps!

3 0
3 years ago
One angle of an isosceles triangle measures 62º. Which other angles could be in that
oee [108]

Answer:

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Step-by-step explanation:

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62, 59, 59

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Answer:

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Step-by-step explanation:

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Choice 2: x²/4 + y²/16 ≤ 1

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try choice 1: 0²/4 + 0²/16  = 0 ≥ 1 (not valid because obviously zero is smaller than 1)  

try choice 1: 0²/4 + 0²/16  = 0 ≤ 1 (this is valid, hence choice 2  is the answer)

4 0
3 years ago
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