3 years ago

Which of the following is the equation of a line perpendicular to the line y=-3/2x+4 passing through the points (3,9)

1 answer:

5 0

<span>Y-y1=m(x-x1)

Y-9 =2/3 (x-3)

Y-9=(2/3)x - 2

Y=(2/3)x + 7

Heres some formulas...</span>

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Katyanochek1 [597]

Answer:

$5xy^3 \sqrt{3x}$

Step-by-step explanation:

The radical $\sqrt{75x^3y^6}$ can be simplified by breaking it down into factors and removing the perfect squares from inside the radical.

$\sqrt{75x^3y^6} =\sqrt{3*25*x^2*x*y^6} =5xy^3 \sqrt{3x}$

25 is a perfect square and is 5 outside the radical.

$x^2$ is a perfect square and is x outside the radical.

$y^6$ is a perfect square and is $y^3$ outside the radical.

7 0

3 years ago

Romashka-Z-Leto [24]

2x=y
x+y=21
x+2x=21
3x=21
x=7
y=2x
y=14

3 0

3 years ago

kupik [55]

Answer:

graph C

Step-by-step explanation:

because the vertex is h,k. h is -3 k is -25. C is the only graph with a vertex at that location.

5 0

3 years ago

Alex777 [14]

Answer:

Ah I-ready. I think maybe the second one

Step-by-step explanation:

8 0

3 years ago

Elodia [21]

49.33, should be right

4 0

3 years ago