An item that was selling for $72.00 is reproduced to $60.00. find the precent decrease in price.

A VW Bug is driving north on a straight two-lane road at a constant 38 mph and a Chevy Impala is driving south at 29 mph on the

vitfil [10]

Those two vehicles are chewing up a lot of ground. Do you drive? I know it's a stupid question. Every American drives, but I have to check. When you see a car coming towards you, does it look like it's going extremely slow, so that 9 could be the answer? Or does it look extremely fast so that 67 could be the answer? I think you should be looking at fast. I live in the country so when something comes towards me I take note of it. So you should be thinking the Impala sees the bug as going north and very fast..

B

Note. The 9 would come up when someone was passing you and they were going 9 mph faster than you were going. If you were going 50 mph and someone passed you at 59 mph. it would appear to you that they were only going 9 mph. Next time you encounter this on the road, see if you agree that that is the way it works.

3 0

3 years ago

One hundred employees of a company are asked how they get to work and whether they work full time or part time. The table below

inna [77]

The probability is 56/100, or 14/25 = 0.56.

These events are not mutually exclusive, meaning they can happen at the same time. This means we use

P(A or B) = P(A) + P(B) - P(A and B)

P(carpool or full time) = P(carpool) + P(full time) - P(carpool & full time)

There are 6+9=15 people out of 100 that carpool.
There are 7+4+30+6=47 people out of 100 that work full time.
There are 6 people out of 100 that carpool and work full time.

This gives us
15/100 + 47/100 - 6/100 = 56/100

5 0

3 years ago

If the probability of selecting, without replacement, 2 red marbles from a bag containing only red and blue marbles is 3 55 and

Marat540 [252]

Answer:

Step-by-step explanation:

Let T = the TOTAL number of marbles in the bag.

We are told that 3 of those marbles are red

P(select a red marble first) = 3/T

Once we've removed the first red marble, there are T-1 marbles remaining and 2 of them are red

So, P(select a red marble second) = 2/(T-1)

Okay, now let's use probability rules to answer the question....

P(select 2 red marbles) = P(select a red marble first AND select a red marble second)

= P(select a red marble first) x P(select a red marble second)

= 3/T x 2/(T-1)

= 6/(T² - T)

We're told that P(select 2 red marbles) = 3/55

So, we can write: 6/(T² - T) = 3/55

Cross multiply to get: 3(T² - T) = (6)(55)

Divide both sides by 3 to get: T² - T = (2)(55)

Evaluate: T² - T = 110

Rearrange: T² - T - 110 = 0

Factor: (T - 11)(T + 10) = 0

So, EITHER T = 11 OR T = -10

Since T cannot be negative, it must be the case that T = 11

6 0

2 years ago

How many positive integers n satisfy the following condition: (130n)^50 > n^100 >2^200

kenny6666 [7]

Answer:

27

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Two more questions , 15 points.

Mumz [18]

The formula that is useful for solving both of these problems is ...

$(v_2)^2-(v_1)^2=2ad\qquad\text{a=acceleration, d=distance}\\\\ \text{where $v_1$ and $v_2$ are initial and final velocities}$

9. Given v₁=15, a=9.8, d=10, find v₂.

... (v₂)² = 15² + 2·9.8·10

... v₂ = √421 ≈ 20.5 . . . . m/s

10. Given d=12 m when a=-9.8 m/s² and v₂=0, find d when a=0.17·(-9.8 m/s²).

The formula tells us that d=(v₁)²/(2a), which is to say that the distance is inversely proportional to the acceleration. If acceleration is 0.17 times that on earth, distance will be 1/0.17 ≈ 5.88 times that on earth.

(12 m)/0.17 ≈ 70.6 m

7 0

3 years ago