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3 years ago

4x^-y^2 what and how would you solve this particular problem

Mathematics

1 answer:

dimulka [17.4K]3 years ago

5 0

It is x^4 - y^2

so, expanding it, (x^2-y)(x^2+y)

hope it served

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Find the probability for the experiment of tossing a coin three times. Use the sample space S = {HHH, HHT, HTH, HTT, THH, THT, T

myrzilka [38]

Answer:

1) 0.375

2) 0.375

3) 0.5

4) 0.5

5) 0.875

6) 0.5

Step-by-step explanation:

We are given the following in the question:

Sample space, S = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}.

$\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}$

1. The probability of getting exactly one tail

P(Exactly one tail)

Favorable outcomes ={HHT, HTH, THH}

$\text{P(Exactly one tail)} = \dfrac{3}{8} = 0.375$

2. The probability of getting exactly two tails

P(Exactly two tail)

Favorable outcomes ={ HTT,THT, TTH}

$\text{P(Exactly two tail)} = \dfrac{3}{8} = 0.375$

3. The probability of getting a head on the first toss

P(head on the first toss)

Favorable outcomes ={HHH, HHT, HTH, HTT}

$\text{P(head on the first toss)} = \dfrac{4}{8} = \dfrac{1}{2} = 0.5$

4. The probability of getting a tail on the last toss

P(tail on the last toss)

Favorable outcomes ={HHT,HTT,THT,TTT}

$\text{P(tail on the last toss)} = \dfrac{4}{8} = \dfrac{1}{2} = 0.5$

5. The probability of getting at least one head

P(at least one head)

Favorable outcomes ={HHH, HHT, HTH, HTT, THH, THT, TTH}

$\text{P(at least one head)} = \dfrac{7}{8} = 0.875$

6. The probability of getting at least two heads

P(Exactly one tail)

Favorable outcomes ={HHH, HHT, HTH,THH}

$\text{P(Exactly one tail)} = \dfrac{4}{8} = \dfrac{1}{2} = 0.5$

3 0

3 years ago

What is 14times25times4

Margaret [11]

1400 is the answer hope this help

7 0

3 years ago

Read 2 more answers

A school bus travels 7 miles in 20 minutes at this rate how long will it take the school bus to complete its entire 45.5 mile ro

BigorU [14]

It would take 2 hours and 10 minutes

7 0

3 years ago

pls help ill give a hundred points. select the correct answer from the drop down menu A(1,3),B(5,3),and D(1,-2) are three vertic

tankabanditka [31]

<h2>Question ↷</h2>

A(1,3),B(5,3),and D(1,-2) are three vertices of rectangle ABCD the coordinates of vertex C are select from the drop down menu (5,2),(-5,1),(5,-2),(2, -5)

<h2>Answer↷</h2>

(5,-2)

<h2>Solution ↷</h2>

we know that,

the midpoint of the diagonals of a rectangle bisect each other,

so,

MP of AC = MP of BD

$\huge \rightarrow \frac{x + 1}{2},\frac{y+ 3}{2} = \frac{5 + 1}{2},\frac{3 - 2}{2} \\$

$\huge \rightarrow \: x = 5 \: \\ \huge \rightarrow \: y = - 2$

3 0

3 years ago

2.57 as a improper fraction

USPshnik [31]

Answer: 2 57/100 hope that helps

6 0

3 years ago