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Sergio039 [100]
3 years ago
12

Difference between flammable and combustible

Chemistry
1 answer:
Nikitich [7]3 years ago
8 0
<h3>flammable liquids will catch on fire and burn easily at normal working temperatures. Combustible liquids have the ability to burn at temperatures that are usually above working temperatures.</h3>

<em>Hope this helped! :)</em>

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What is the number of copper atom in one naira coin which weight is 7.3g a sum of the material is 86%
Step2247 [10]

Answer:

5.9x10²² atoms of Cu are in one naira coin

Explanation:

To solve this question we need to find the mass of Copper. Then, using its molar mass (Cu = 63.546g/mol) we must find the moles of Cu and its atoms using Avogadro's number:

<em>Mass Cu:</em>

7.3g * 86% = 6.278g is the mass of Cu.

<em>Moles Cu:</em>

6.278g * (1mol / 63.546g) = 0.099moles Cu

<em>Atoms Cu:</em>

0.099moles Cu * (6.022x10²³atoms / 1mol) =

<h3>5.9x10²² atoms of Cu are in one naira coin</h3>
4 0
3 years ago
what happens when a gas obtained by heating Ammonium Chloride and slaked lime are passed through copper sulphate ?​
gogolik [260]

Answer:

Consequently, what happens when gas obtained by heating slaked lime and ammonium chloride is passed through copper sulphate solution? The HCl in the gas mixture will form hydrochloric and the H+ will react with some of the NH3(aq), forming NH4^+, and with some of the SO4^2-, forming HSO4^-.

8 0
3 years ago
How do you think our understanding of genes might affect doctors ability to treat or prevent disease in the future?
igomit [66]

Answer:

dentifying genetic variants Genome sequencing has the potential to improve the diagnosis of conditions caused by changes in the DNA and indicate what treatments may be most effective. Importantly, it may also red-flag treatments likely to cause adverse reactions.

Explanation:

3 0
3 years ago
Read 2 more answers
Lt takes 4 hr 39 min for a 2.00-mg sample of radium-230 to decay to 0.25 mg. what is the half-life of radium-230?
Rufina [12.5K]
Radioactive decay => C = Co { e ^ (- kt) |

Data:

Co = 2.00 mg
C = 0.25 mg
t = 4 hr 39 min

Time conversion: 4 hr 39 min = 4.65 hr

1) Replace the data in the equation to find k

C = Co { e ^ (-kt) } => C / Co = e ^ (-kt) => -kt = ln { C / Co} => kt = ln {Co / C}

=> k = ln {Co / C} / t =  ln {2.00mg / 0.25mg} / 4.65 hr = 0.44719

2) Use C / Co  = 1/2 to find the hallf-life

C / Co = e ^ (-kt) => -kt = ln (C / Co)

=> -kt = ln (1/2) => kt = ln(2) => t = ln (2) / k

t = ln(2) / 0.44719 = 1.55 hr.

Answer: 1.55 hr
6 0
4 years ago
I can hit a metal with a hammer without the metal shattering because of its
kati45 [8]

Answer: Malleability

Explanation: cuz ... its right ... lol

8 0
3 years ago
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