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Sergeeva-Olga [200]
3 years ago
8

A large piece of jewelry has a mass of 132.6 g. a graduated cylinder initially contains 48.6 ml water. when the jewelry is subme

rged in the graduated cylinder, the total volume increases to 61.2 ml. determine the density of this piece of jewelry. assuming that the jewelry is made from only one substance, what substance is it likely to be? explain.
Chemistry
1 answer:
Simora [160]3 years ago
4 0

Answer:- Density is 10.5 grams per mL and the substance is Silver(Ag).

Solution:-  Mass of jewelry is given as 132.6 g. Initial volume of water in the graduated cylinder is 48.6 mL and the volume becomes 61.2 mL when this jewelry is submerged in the cylinder.

So, the volume of the jewelry = 61.2 mL - 48.6mL = 12.6 mL

We know that, density=\frac{mass}{volume}

Let's plug in the values in the above formula to calculate the density:

density=\frac{132.6g}{12.6mL}

density=10.5\frac{g}{mL}

So, the density of the jewelry is 10.5\frac{g}{mL} .

The substance from which the jewelry is made could easily be identified by comparing the calculated density with the density values given for different substances in the density table.

Looking at the density table, 10.5 grams per mL is the density for silver. So, the jewelry is made up from Silver.

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Answer:

Explanation:

The trick here is to realize that if you know the volume of a gas at STP, you can use the fact that

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Under STP conditions:

1 mole of an ideal gas = 22.7 L

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In your case, you know that your sample of gas occupies

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

1 mole gas

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1

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8 0
2 years ago
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A balloon is filled to a volume of 1.50 L with 3.00 moles of gas at 25 °C. With pressure and temperature held constant, what wil
Ludmilka [50]

Answer:

Volume : 1.25 L

Explanation:

We are given here that the volume ( V_1 ) = 1.50 Liters, the initial moles ( held at 25 °C ) = 3.00 mol, and the final moles ( n_2 ) = 3.00 - 0.5 = 2.5 mol. The final mol is calculated given that 0.50 mol of gas are released from the prior 3.00 moles of gas.

Volume ( V_1 ) = 1.50 L,

Initial moles ( n_1 ) = 3.00 mol,

Final Volume ( n_2 ) = 3.00 - 0.5 = 2.5 mol

Applying the combined gas law, we can calculate the final volume ( V_2 ).

P_1V_1 / n_1T_1 = P_2V_2 / n_2T_2 - we know that the pressure and temperature are constant, and therefore we can apply the following formula,

V_1 / n_1 = V_2 / n_2 - isolate V_2,

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6 0
3 years ago
Name Any two metal which are not ductile
scoray [572]

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Any two metal which are not ductile are iron and zinc ..

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2 years ago
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What is the enthalpy of reaction?
erma4kov [3.2K]

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3 years ago
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Answer:

128.4 m

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I hope this helps!

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