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Evgen [1.6K]
3 years ago
8

Acidic solutions contain high concentrations of

Chemistry
1 answer:
finlep [7]3 years ago
6 0

Answer:

hydrogen ions

Explanation:

because acid is the specie that have ability to donate proton or forming bond with electron pair

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What is a wave produced by vibrating electric charges that can travel in matter and empty space?
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The answer is A

Explanation:
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Mercury may have lost part of its mantle and crust to a _______ leaving it with a large, metal _______.
igomit [66]
<h2>Giant impact and metalcore.</h2>

Explanation :

  • Mercury has a large core of liquid metal.
  • The metal core is of iron metal.
  • The core is surrounded by a mantle which is made up of silica and a solid outer crust.
  • In the case of Mercury, the total core percentage is 42% of the planet while the Earth's core is only 17% of the planet.
  • Mercury has lost part of its mantle and crust that left the mercury with a large metal core.

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3 years ago
Explain electronegativity and how it relates to both molecular and ionic bonding.
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3 0
2 years ago
A sample of an unknown metal has a mass of 58.932g. it has been heated to 101.00 degrees C, then dropped quickly into 45.20 mL o
yaroslaw [1]
<h3>Answer:</h3>

0.111 J/g°C

<h3>Explanation:</h3>

We are given;

  • Mass of the unknown metal sample as 58.932 g
  • Initial temperature of the metal sample as 101°C
  • Final temperature of metal is 23.68 °C
  • Volume of pure water = 45.2 mL

But, density of pure water = 1 g/mL

  • Therefore; mass of pure water is 45.2 g
  • Initial temperature of water = 21°C
  • Final temperature of water is 23.68 °C
  • Specific heat capacity of water = 4.184 J/g°C

We are required to determine the specific heat of the metal;

<h3>Step 1: Calculate the amount of heat gained by pure water</h3>

Q = m × c × ΔT

For water, ΔT = 23.68 °C - 21° C

                       = 2.68 °C

Thus;

Q = 45.2 g × 4.184 J/g°C × 2.68°C

    = 506.833 Joules

<h3>Step 2: Heat released by the unknown metal sample</h3>

We know that, Q =  m × c × ΔT

For the unknown metal, ΔT = 101° C - 23.68 °C

                                              = 77.32°C

Assuming the specific heat capacity of the unknown metal is c

Then;

Q = 58.932 g × c × 77.32°C

   = 4556.62c Joules

<h3>Step 3: Calculate the specific heat capacity of the unknown metal sample</h3>
  • We know that, the heat released by the unknown metal sample is equal to the heat gained by the water.
  • Therefore;

4556.62c Joules = 506.833 Joules

c = 506.833 ÷4556.62

  = 0.111 J/g°C

Thus, the specific heat capacity of the unknown metal is 0.111 J/g°C

8 0
3 years ago
The Earth’s atmosphere is divided into five layers. In which layer does all life exist?
n200080 [17]

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2. less dense/decreases

3. ozone

4. nitrogen

5. xylem

6. flagellum

7. kingdom fungi

8. Ocean convection currents

9. As they fly, insects spread pollen that sticks to their bodies from the flowers.

10. the plastic handle, because it is a good insulator.

11. The hyphae, or feeding structures, reach deep into the wood to obtain nutrients

12. chemical energy

13. created or destroyed.

14. electromagnet

15. c

16. kinetic, elastic potential

5 0
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