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fenix001 [56]
3 years ago
12

Barry has 64 butterflies in his collection. He gave half of them to his sister and 12 to his brother. How many butterflies does

Barry have left in his collection?
Mathematics
2 answers:
Soloha48 [4]3 years ago
6 0
Half of 64 = 32 
32 + 12 = 44
64 - 44 = 20
Barry has 20 butterflies left!
kotykmax [81]3 years ago
5 0
64/2=32-12=20 Barry has 20 butterflies left in his collection

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Increase £14187.13 by 14.5%
zhenek [66]

Answer:

16,244.26

Step-by-step explanation:

14,187.13 + (14.5% × 14,187.13) =

14,187.13 + 14.5% × 14,187.13 =

(1 + 14.5%) × 14,187.13 =

(100% + 14.5%) × 14,187.13 =

114.5% × 14,187.13 =

114.5 ÷ 100 × 14,187.13 =

114.5 × 14,187.13 ÷ 100 =

1,624,426.385 ÷ 100 =

16,244.26385 ≈

5 0
3 years ago
Read 2 more answers
Use linear approximation to approximate √25.3 as follows.
Sophie [7]

The idea is to use the tangent line to f(x)=\sqrt x at x=25 in order to approximate f(25.3)=\sqrt{25.3}.

We have

f(x)=\sqrt x\implies f(25)=\sqrt{25}=5

f'(x)=\dfrac1{2\sqrt x}\implies f'(25)=\dfrac1{10}

so the linear approximation to f(x) is

L(x)=f(5)+f'(5)(x-5)=5+\dfrac{x-5}{10}=\dfrac x{10}+\dfrac92

Hence m=\frac1{10} and b=\frac92.

Then

f(25.3)\approx L(25.3)=\dfrac{25.3}{10}+\dfrac92=\boxed{7.03}

4 0
3 years ago
Pleaseee i need help!! and the working!
zaharov [31]
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Then to change it back you:
$49,000 divided by 1.75 = £28,000
6 0
3 years ago
Write an equasion of the line in point-slope form that passes through the points (-16, 8) (4,2)
xeze [42]
You start by finding the slope :  y2 - y1 / x2 - x1

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                                           m =  - 3 / 10 

Point slope form :  y - y1 = m( x- x1 )

           You can pick either of the coordinates and substitute them in

 POINT SLOPE FORM EQUATION   : y - 8 = -3/10 ( x + 16 )

5 0
3 years ago
I need help with this please
Levart [38]
Yu can you think how many triangles fit in that parallelogram? The answer is six. four in the central rectangle and two at the ends, then the area of ​​the parallelogram will be six times greater than that of the triangle in that graph. Good luck! M.
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3 years ago
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