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Arada [10]
3 years ago
6

What is 12/25 divided by 4

Mathematics
2 answers:
UNO [17]3 years ago
5 0
In order to find the answer to this, you must first turn 4 into a fraction (4/1)

12/25 divided by 4/1 is the same as 12/25 multiplied by 1/4, because when dividing fractions, you must use the reciprocal of the divisor and multiply.

12/25 x 1/4 = 12/100 = 6/50 = 3/25

Your answer should be 3/25<span />
vladimir1956 [14]3 years ago
3 0
0.12 is the answer. You can always get the app called photomath it helps!
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Use synthetic division to solve (4x-3x+5x+6)/(x+6). What is the quotient?
Andrei [34K]

The correct solution: 4x^2 -27x +167 - 996/(x+6)

Step-by-step explanation:


5 0
3 years ago
Car A's fuel efficiency is 34 miles per gallon of gasoline, and car B's fuel efficiency is 23 miles per gallon of gasoline. At t
Verdich [7]

Answer:

22 more gallons.

Step-by-step explanation:

Given:

Car A's fuel efficiency is 34 miles per gallon of gasoline.

Car B's fuel efficiency is 23 miles per gallon of gasoline.

Question asked:

At those rates, how many more gallons of gasoline would car B consume than car A on a 1,564 miles trip?

Solution:

<u>Car A's fuel efficiency is 34 miles per gallon of gasoline.</u>

<u>By unitary method:</u>

Car A can travel 34 miles in = 1 gallon

Car A can travel 1 mile in = \frac{1}{34} \ gallon

Car A can travel 1564 miles in = \frac{1}{34} \times1564=46\ gallons

<u>Car B's fuel efficiency is 23 miles per gallon of gasoline.</u>

Car B can travel 23 miles in = 1 gallon

Car B can travel 1 mile in = \frac{1}{23} \ gallon

Car B can travel 1564 mile in = \frac{1}{23} \times1564=68\ gallons

We found that for 1564 miles trip Car A consumes 46 gallons of gasoline while  Car B consumes 68 gallons of gasoline that means Car B consumes 68 - 46 = 22 gallons more gasoline than Car A.

Thus, Car B consumes 22 more gallons of gasoline than Car A consumes.

<u />

6 0
3 years ago
Explain why any of the four operations placed between two terms 5 and -3 sqrt (8) will result in an irrational number
Gnoma [55]

Sum/difference:

Let

x = 5 + (-3\sqrt{8}) = 5-3\sqrt{8}

This means that

3\sqrt{8} = 5-x \iff \sqrt{8} = \dfrac{5-x}{3}

Now, assume that x is rational. The sum/difference of two rational numbers is still rational (so 5-x is rational), and the division by 3 doesn't change this. So, you have that the square root of 8 equals a rational number, which is false. The mistake must have been supposing that x was rational, which proves that the sum/difference of the two given terms was irrational

Multiplication/division:

The logic is actually the same: if we multiply the two terms we get

x = -15\sqrt{8}

if again we assume x to be rational, we have

\sqrt{8} = -\dfrac{x}{15}

But if x is rational, so is -x/15, and again we come to a contradiction: we have the square root of 8 on one side, which is irrational, and -x/15 on the other, which is rational. So, again, x must have been irrational. You can prove the same claim for the division in a totally similar fashion.

7 0
2 years ago
What’s the answer ??
CaHeK987 [17]

Answer:

The answer is A.

Step-by-step explanation:


5 0
3 years ago
Find three consecutive integers such that that product of the first and third is one
Tema [17]

Answer:

n = the first

n + 1 = the 2nd

n + 2 = the 3rd

n(n + 2) - (n + 1) = 10(n + 2) + 1

n2 + 2n - n - 1 = 10n + 20 + 1

n2 - 9n - 22 = 0

(n - 11)(n + 2) = 0

If two factors = 0, at least one must = 0.

n - 11 = 0

n = 11

11,12,13

n + 2 = 0

n = -2

-2,-1,0

7 0
2 years ago
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