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aliina [53]
3 years ago
12

4k – 6 = -2k – 16 – 2

Mathematics
1 answer:
Nesterboy [21]3 years ago
3 0
K is equal to negative two
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Can someone figure out the problem in this image?
erma4kov [3.2K]
Right side:
(1/27)^(2x+10)
=(3^-3)^(2x+10)
= 3^(-6x - 30)

Re-write both sides:
3^(4x-5) = 3^(-6x - 30)

from here, you can solve x 

4x - 5 = -6x - 30
4x + 6x = -30 + 5
10x = -25
    x = -2.5
7 0
4 years ago
2. Calculate the energy in joules of a photon whose frequency is 7.55×1014 Hz.
igomit [66]
The energy of a photon is given by
E = h × v

where:
E is the energy in joules/photon
'h' is the constant 6.63 × 10⁻³⁴
'v' is the frequency 7.55 × 10¹⁴

Substitute 'h' and 'v' into the formula we have

E = (6.63×10⁻³⁴) × (7.55×10¹⁴)
E = (6.63×7.55) × (10⁻³⁴ × 10¹⁴)
E = 50.0565 × 10⁽⁻³⁴⁺¹⁴⁾
E = 50 × 10⁻²⁰ joules/photon
8 0
3 years ago
Use abc to find the value of sin a
kolbaska11 [484]

sin α = opposite leg/ hypotenuse

For ΔABC,

sin A = |BC|/|AB|

sin A = 12/37

7 0
3 years ago
I need help figuring this out asap please
Vera_Pavlovna [14]

Answer:

38.13 ft squared

Step-by-step explanation:

Since it is half of a circle we first find the area of a normal circle then divide by two.

So to find the area of  a circle it is pi times radius squared which in this case it would be 3.14 times 9 = 28.26

Then since it is a half circle we divide by two so

28.26/2 = 14.13

Then to find the area of the triangle we do 4 times 6 which is 24.

now we add the two which is 14.13 + 24 which is

38.13

4 0
3 years ago
A square is shown below. Which expression can be used to find the area, in square units, of the shaded triangle in the square?
ELEN [110]

Answer:

Area = \frac{1}{2} (6)(6)

Step-by-step explanation:

Area of Triangle = \frac{1}{2} (Base)(Height)

Where Base = 6 , Height = 6

Area = \frac{1}{2} (6)(6)

Area = 3 * 6

<u><em>Area = 18 units^2</em></u>

7 0
3 years ago
Read 2 more answers
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