Answer:

Step-by-step explanation:
<h2>Equation of line in slope y-intercept form:</h2>

![\sf y - [-3] = \dfrac{1}{2}(x - 2)\\\\y + 3 = \dfrac{1}{2}x - 2*\dfrac{1}{2}\\\\y + 3 = \dfrac{1}{2}x-1\\\\](https://tex.z-dn.net/?f=%5Csf%20y%20-%20%5B-3%5D%20%3D%20%5Cdfrac%7B1%7D%7B2%7D%28x%20-%202%29%5C%5C%5C%5Cy%20%2B%203%20%3D%20%20%5Cdfrac%7B1%7D%7B2%7Dx%20-%202%2A%5Cdfrac%7B1%7D%7B2%7D%5C%5C%5C%5Cy%20%2B%203%20%3D%20%5Cdfrac%7B1%7D%7B2%7Dx-1%5C%5C%5C%5C)

Answer: PEMDAS
8•2 = 16
16+3x = -7
-3 -3
16 + x = -10
-16 -16
X= -26
Step-by-step explanation:
Answer: D
<u>Step-by-step explanation:</u>
The first matrix contains the coefficients of the x- and y- values for both equations (top row is the top equation and the bottom row is the bottom equation. The second matrix contains what each equation is equal to.
![\begin{array}{c}2x-y\\x-6y\end{array}\qquad \rightarrow \qquad \left[\begin{array}{cc}2&-1\\1&-6\end{array}\right] \\\\\\\begin{array}{c}-6\\13\end{array}\qquad \rightarrow \qquad \left[\begin{array}{c}-6\\13\end{array}\right]](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bc%7D2x-y%5C%5Cx-6y%5Cend%7Barray%7D%5Cqquad%20%5Crightarrow%20%5Cqquad%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-1%5C%5C1%26-6%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5C%5C%5C%5Cbegin%7Barray%7D%7Bc%7D-6%5C%5C13%5Cend%7Barray%7D%5Cqquad%20%5Crightarrow%20%5Cqquad%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D-6%5C%5C13%5Cend%7Barray%7D%5Cright%5D)
The product will result in the solution for the x- and y-values of the system.
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