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3 years ago

7

frank is choosing a 2 letter password from the letters A B C D and E. the password cannot have the same letter repeated in it. h

ow many such passwords are possible

2 answers:

Zarrin [17]3 years ago

8 0

20 possible combinations

Georgia [21]3 years ago

3 0

You can have ten choices

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With 128 134 140 146 152 what's the next number if the pattern continues

Lina20 [59]

158, it's going up by 6 every time.

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4 years ago

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Need help with these plzz wen i get all the correct answers i will friend u and give u 42 more points.

sveta [45]

Answer:

By using pythagoras formula

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The following table shows the values of y for different values of x:

solmaris [256]

Answer:

Option B. It represents a nonlinear function because its points are not on a straight line.

Step-by-step explanation:

Let

$A(0,0),B(1,1),C(2,4)$

we know that

If point A,B and C are on a straight line

then

The slope of AB must be equal to the slope of AC

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

<em>Find the slope AB</em>

$A(0,0),B(1,1)$

substitute in the formula

$m_A_B=\frac{1-0}{1-0}=1$

<em>Find the slope AC</em>

$A(0,0),C(2,4)$

substitute in the formula

$m_A_C=\frac{4-0}{2-0}=2$

so

$m_A_B\neq m_A_C$

Points A, B and C are not on a straight line

therefore

It represents a nonlinear function because its points are not on a straight line

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3 years ago

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The number of failures of a testing instrument from contamination particles on the product is a Poisson random variable with a m

Mazyrski [523]

Answer:

The probability that the instrument does not fail in an 8-hour shift is $P(X=0) \approx 0.8659$

The probability of at least 1 failure in a 24-hour day is $P(X\geq 1 )\approx 0.3508$

Step-by-step explanation:

The probability distribution of a Poisson random variable X representing the number of successes occurring in a given time interval or a specified region of space is given by the formula:

$P(X)=\frac{e^{-\mu}\mu^x}{x!}$

Let X be the number of failures of a testing instrument.

We know that the mean $\mu = 0.018$ failures per hour.

(a) To find the probability that the instrument does not fail in an 8-hour shift, you need to:

For an 8-hour shift, the mean is $\mu=8\cdot 0.018=0.144$

$P(X=0)=\frac{e^{-0.144}0.144^0}{0!}\\\\P(X=0) \approx 0.8659$

(b) To find the probability of at least 1 failure in a 24-hour day, you need to:

For a 24-hour day, the mean is $\mu=24\cdot 0.018=0.432$

$P(X\geq 1 )=1-P(X=0)\\\\P(X\geq 1 )=1-\frac{e^{-0.432}0.432^0}{0!}\\\\P(X\geq 1 )\approx 0.3508$

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3 years ago

Someone who is a true hero plz answer this for me I need help

nevsk [136]

Answer:

4√2 or 5.66 to the nearest hundredth.

Step-by-step explanation:

Applying the Pythagoras Theorem:_

c^2 = a^2 + b^2

c^2 = 4^2 + 4^2

c^2 = 32

c = √32

c = 4√2

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3 years ago