Beth's speed was 60 mph.
<h3>
What is speed?</h3>
- The speed (commonly referred to as v) of an object in everyday use and kinematics is the magnitude of the change in its position over time or the magnitude of the change in its position per unit of time; it is thus a scalar quantity.
- The distance traveled by an object in a time interval is divided by the duration of the interval; the instantaneous speed is the limit of the average speed as the duration of the time interval approaches zero.
- Velocity is not the same as speed.
To find what was Beth's speed:
Beth's data:
- time = 2 hrs; rate = r mph; distance = r×t = 2r miles
Tim's data:
- time = 1 hr; rate = r-6 mph; distance = r-6 miles
Equation:
- distance + distance = 174 miles
So,
- 2r + r - 6 = 174
- 3r - 6 = 174
- 3r = 180
- r = 60 mph (Beth's rate)
- r-6 = 54 mph (Tims's rate)
Therefore, Beth's speed was 60 mph.
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Answer:
13 cups
Step-by-step explanation:
1.5 pint= 3 cups
8 fluid ounces = 1 cup
4 bottles of milk with 1.5 pint each= 3x 4= 12 cup
8 fluid ounces of strawberry syrup= 1 cup
12+1=13 cups
If two secants intersect from a point outside of the circle, then the product of the lengths of the secant and its external segment equals the product of the other secant and its external segment.
#1
5(x+5) = 6(4+6)
5x + 25 = 6 * 10
5x = 60 - 25
5x = 35
x = 7
#2
4(x+4) = 3(5+3)
4x + 16 = 3 * 8
4x = 24 - 16
4x = 8
x = 8/4
x = 2
Answer:
13.66
Step-by-step explanation:
In the picture above
f(x)=x3−5
Replace f(x)
with y
.
y=x3−5
Interchange the variables.
x=y3−5
Solve for y
.
Since y
is on the right side of the equation, switch the sides so it is on the left side of the equation.
y3−5=x
Add 5
to both sides of the equation.
y3=5+x
Take the cube root of both sides of the equation to eliminate the exponent on the left side.
y=3√5+x
Solve for y
and replace with f−1(x)
.
Replace the y
with f−1(x)
to show the final answer.
f−1(x)=3√5+x
Set up the composite result function.
f(g(x))
Evaluate f(g(x))
by substituting in the value of g into f
.
(3√5+x)3−5
Simplify each term.
Remove parentheses around 3√5+x
.
f(3√5+x)=3√5+x3−5
Rewrite 3√5+x3
as 5+x
.
f(3√5+x)=5+x−5
Simplify by subtracting numbers.
.
Subtract 5
from 5
.
f(3√5+x)=x+0
Add x
and 0
.
f(3√5+x)=x
Since f(g(x))=x
, f−1(x)=3√5+x is the inverse of f(x)=x3−5
.
f−1(x)=3√5+x
