We can solve this problem by referring to the standard
probability distribution tables for z.
We are required to find for the number of samples given the
proportion (P = 5% = 0.05) and confidence level of 95%. This would give a value
of z equivalent to:
z = 1.96
Since the problem states that it should be within the true
proportion then p = 0.5
Now we can find for the sample size using the formula:
n = (z^2) p q /E^2
where,
<span> p = 0.5</span>
q = 1 – p = 0.5
E = estimate of 5% = 0.05
Substituting:
n = (1.96^2) 0.5 * 0.5 / 0.05^2
n = 384.16
<span>Around 385students are required.</span>
AC = 28
Step-by-step explanation:
Answer:
418 4/10
Step-by-step explanation:
To answer this we subtract 450 7/10 from 869 1/10.
We must borrow a '1' from 869 1/10: 868 11/10
Now subtract 450 7/10 from 868 11/10:
418 4/10 (CHANGE IN ELEVATION)
This reduces to 418 2/5.
The answer is $654.06.
5.5% of $575 is $31.63. 575 x 0.055 = 31.63
This means that in one year he earns $31.63. In two years it will be $63.25 (31.63 x 2 = 63.25)
Then in half a year it will be $15.81 (31.63/2 = 15.81)
Finally add 15.81 and 63.25 to get $79.06 which you then add to the initial $575 to get the total amount earned in 2 1/2 years which is $654.06.
Answer:
32
Step-by-step explanation:
First, combine like terms
4x+7=6x-9
+9 +9
4x+16=-9
-16 -16
Then divide by four to isolate x
4x=-25
x=-6.25
Plug in X to get the angle measure .
