Answer: points B (4,7) and I (9,3)
If the inequalities are
y > −2x + 10 and y> (½)x -2
Step-by-step explanation: If I interpreted the inequalities correctly, the attached graph shows them. It is possible that you meant y > 1/(2x-2) for the second inequality. If so, we start over!
You can test the values for all the points, but it appears that (4,7) and (9,3) both work.
The other coordinates appear to be outside the solution -- the dark-shaded area.
I hope this is your Brainliest answer. It was a lot of work!
Answer 5.5
Explanation 125 + 125= 250
250 + 50=300
Is 2 125s and 1 50
Each 125 is 2.5
But in this case there is 2 125s
2.5+2.5=5
plus the other half = 5.5
BRAINLIST?
Answer:
addie at 4.5 candie bars and frankie had 4
Simplifying -2x + -3y = -7
Solving -2x + -3y = -7
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '3y' to each side of the equation. -2x + -3y + 3y = -7 + 3y
Combine like terms: -3y + 3y = 0 -2x + 0 = -7 + 3y -2x = -7 + 3y
Divide each side by '-2'. x = 3.5 + -1.5y Simplifying x = 3.5 + -1.5y
The cost of children’s ticket is $ 5
<h3><u>Solution:</u></h3>
Let "c" be the cost of one children ticket
Let "a" be the cost of one adult ticket
Given that adult ticket to a museum costs 3$ more than a children’s ticket
<em>Cost of one adult ticket = 3 + cost of one children ticket</em>
a = 3 + c ------ eqn 1
<em><u>Given that 200 adult tickets and 100 children tickets are sold, the total revenue is $2100</u></em>
200 adult tickets x cost of one adult ticket + 100 children tickets x cost of one children ticket = 2100
200a + 100c = 2100 ------ eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>
Substitute eqn 1 in eqn 2
200(3 + c) + 100c = 2100
600 + 200c + 100c = 2100
600 + 300c = 2100
300c = 1500
<h3>c = 5</h3>
Thus the cost of children’s ticket is $ 5
