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Papessa [141]
3 years ago
11

Select the correct answer. Wayne plays multiple instruments in a rock band. He also composes the songs. He takes 36 weeks to wri

te the songs for an album of 12 songs. If you assume he takes an equal amount of time to compose each song and graph this relationship with the number of weeks on the x-axis and the number of songs on the y-axis, what is Wayne's unit rate for composing a song?
Mathematics
1 answer:
Reil [10]3 years ago
7 0

Answer:

3 weeks for one song

Step-by-step explanation:

The function would be y = 3x + b

You might be interested in
(4×⁴+3׳+2ײ-×+1)+(5ײ-2×+3)​
Annette [7]

Answer:

4×⁴+3׳+7ײ-3x+4

Step-by-step explanation:

First remove the parentheses and pair up like terms

4×⁴+3׳+2ײ+5ײ-x-2x+1+3

Then combine the like terms

4×⁴+3׳+7ײ-3x+4

Which is the answer.

3 0
3 years ago
What function was used to make that pattern​
Semenov [28]

Answer:

B

Step-by-step explanation:

The differences in the terms of f(x) are + 3, + 5, + 7

Since the differences are not constant the relationship is not linear

Note the differences in the differences are + 2, + 2,

The second differences are constant indicating a quadratic relationship

Note the relationship between x and f(x)

x = 1 → 1² = 1 ← require to add 5, that is 1 + 5 = 6 ← value of f(x)

x = 2 → 2²  = 4 ← require to add 5, that is 4 + 5 = 9 ← value of f(x)

x = 3 → 3² = 9 ← require to add 5, that is 9 + 5 = 14 ← value of f(x)

x = 4 → 4² = 16 ← require to add 5, that is 16 + 5 = 21 ← value of f(x)

Thus f(x) = x² + 5 → B

3 0
3 years ago
Unit 3 | Lesson 9
Charra [1.4K]
The formula d = rt gives the distance traveled in time t at rate r. A bicyclist rides for 1.5 hours and travels 25 miles. 
d= D. 37.5 miles per hour
r= 25
t=1.5
25*1.5
=37.5

D.
37.5 miles per hour
5 0
3 years ago
A certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder. In
lord [1]

Answer:

95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

Step-by-step explanation:

We are given that a certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder.

A random sample of 1000 males, 250 are found to be afflicted, whereas 275 of 1000 females tested appear to have the disorder.

Firstly, the pivotal quantity for 95% confidence interval for the difference between population proportion is given by;

                        P.Q. = \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }  ~ N(0,1)

where, \hat p_1 = sample proportion of males having blood disorder= \frac{250}{1000} = 0.25

\hat p_2 = sample proportion of females having blood disorder = \frac{275}{1000} = 0.275

n_1 = sample of males = 1000

n_2 = sample of females = 1000

p_1 = population proportion of males having blood disorder

p_2 = population proportion of females having blood disorder

<em>Here for constructing 95% confidence interval we have used Two-sample z proportion statistics.</em>

<u>So, 95% confidence interval for the difference between the population proportions, </u><u>(</u>p_1-p_2<u>)</u><u> is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                             of significance are -1.96 & 1.96}  

P(-1.96 < \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } < {(\hat p_1-\hat p_2)-(p_1-p_2)} < 1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } ) = 0.95

P( (\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } < (p_1-p_2) < (\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } ) = 0.95

<u>95% confidence interval for</u> (p_1-p_2) =

[(\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }, (\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }]

= [ (0.25-0.275)-1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} }, (0.25-0.275)+1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} } ]

 = [-0.064 , 0.014]

Therefore, 95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

8 0
3 years ago
A pair of shoes is currently priced at $55.00. If the store manager marks it down to $22.00, by what percent did he mark down th
telo118 [61]

Answer:

60%

Step-by-step explanation:

55 - 22 = 33

33/55 = 0.6

0.6*100 = 60%

6 0
3 years ago
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