A spherical weather balloon is being inflated. The radius of the balloon is increasing at the rate of 7 cm/s. Express the surfac
e area of the balloon as a function of time t (in seconds). (Let S(0) = 0.) . S(t) = cm^2?
2 answers:
R(t) = 6t
<span>putting into the formula </span>
<span>V = (4/3) pi * r^3 </span>
<span>V(t) = (4/3) pi * (6t)^3 </span>
<span> </span>
<span>V(t) = (4/3) pi * 216 t^3
Multiply the 4/3 by the 216 and </span>
<span>V(t) = 288 * pi * t^3</span>
Answer:

Step-by-step explanation:
We are given that
Radius of balloon increasing at the rate= 7 cm/s
Let time= t seconds
In 1 second radius =7 cm
In t second radius =R(t) = 7 t
We have to find the surface area of balloon as function of time t
We know that area of sphere=S(R)=
Substitute the value

Hence, 
You might be interested in
Answer:
Fax
Step-by-step explanation:
A . 13 cm is the correct answer
Answer:
$85.2
Step-by-step explanation:
Your answer is B) 1.05 x 10 5
857 x 132= 113,124
work is showed in the image