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3 years ago

Todd begins piano practice at 4:15 P.M. and ends at 5:50 P.M. How long does he practice?

Mathematics

2 answers:

marta [7]3 years ago

7 0

If He began at 4:15 and ended at 5:50 then that would be 95 minutes

Verizon [17]3 years ago

5 0

95 minutes because:-

The distance between 4:15 and 5:50 is 95 minutes.

Answer: 95 minutes

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A number is increased by 54. The sumos then divided by 9. The result is 21. Write an equation to represent the discription, use

hram777 [196]

Answer:

(n+54)/9 = 21

Step-by-step explanation:

A number: n

Is increased by 54: n+54

The sum is divided by 9: (n +54)/9

and the result is 21:

(n +54)/9 = 21

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3 years ago

Affirmative action programs are primarily intended to . Allan Bakke believed he had been rejected for admission solely because o

Papessa [141]

Answer:

Encourage diversity

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Step-by-step explanation:

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3 years ago

On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th

Elena L [17]

Answer:

The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, a = $\sqrt{(3-0)^{2}+(4-0)^{2}}$

Or, a = $\sqrt{9+16}$

Or, a = $\sqrt{25}$

∴ a = 5 unit

Similarly

The measure of length BC = b = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, b = $\sqrt{(3-3)^{2}+(2-4)^{2}}$

Or, a = $\sqrt{0+4}$

Or, b = $\sqrt{4}$

∴ b = 2 unit

And

So, The measure of length CA = c = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, c = $\sqrt{(3-0)^{2}+(2-0)^{2}}$

Or, c = $\sqrt{9+4}$

Or, c = $\sqrt{13}$

∴ c = $\sqrt{13}$ unit

Now, area of Triangle written as , from Heron's formula

A = $\sqrt{s\times (s-a)\times (s-b)\times (s-c)}$

and s = $\frac{a+b+c}{2}$

I.e s = $\frac{5+2+\sqrt{13}}{2}$

Or. s = $\frac{7+\sqrt{13}}{2}$

So, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}$

Or, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}$

Or, A = $\frac{3}{2}$ × $\sqrt{1+\sqrt{13} }$

∴ Area of triangle = 1.5 $\sqrt{4.6}$

Hence The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$ Answer

7 0

3 years ago

Read 2 more answers

Help quick I’m timed How many edges does the figure have?<br> 6<br> 8<br> 12<br> 24

gulaghasi [49]

Answer:

A rectangular prism has 12 edges.

5 0

3 years ago

Read 2 more answers

Surface area of 18 12 and 4 plz help!

Liula [17]

You would start off by finding the base, which is 18*12. That equals 216 meters squared, you multiply that by 2 to get the surface area of your 2 bases. That equals 432 meters squared. To find the surface area of the sides (on the left and right side), you would use the equation length times height. To plug in the numbers, you use 12*4, that is 48 meters squared. There are 2 sides, so multiply by 2, to get 96 meters squared. To find the last side, you take length times width, plug in the numbers. Those numbers are 4*18, which equals 72 meters squared. Once again, there are two sides, so you multiply by 2, to get 144 meters squared. Next, as the final step, you add up all of the final numbers. They are: 432+96+144 which equals 672 meters squared.

Your final answer is 672 meters squared.

I hope this helps!

5 0

3 years ago