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2 years ago

How do you know where to place the decimal in a quotient?

Mathematics

2 answers:

stealth61 [152]2 years ago

6 0

It all depends on the divisor.

You need to make sure the decimal of the divisor is at the end.

For example, 2.09 divided by 0.19

You need to move the decimal point of 0.19 two times to the right so the decimal point is at the end.

If the divisor is a whole number, the decimal would stay at the same position.

For example, 25.5 divided by 5, the decimal would stay since 5's decimal point is already at the end (5.)

See attachment if you want to see it visual. Writing on computer is hard tho.

g100num [7]2 years ago

3 0

Answer:

Take note that the quotient's decimal point is precisely above the dividend's decimal point. To divide a decimal by a whole number, move the decimal point in the quotient above the decimal point in the dividend and divide as usual.

Step-by-step explanation:

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Suppose 52% of the population has a college degree. If a random sample of size 563563 is selected, what is the probability that

amm1812

Answer:

The value is $P(| \^ p - p| < 0.05 ) = 0.9822$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.52$

The sample size is n = 563

Generally the population mean of the sampling distribution is mathematically represented as

$\mu_{x} = p = 0.52$

Generally the standard deviation of the sampling distribution is mathematically evaluated as

$\sigma = \sqrt{\frac{ p(1- p)}{n} }$

=> $\sigma = \sqrt{\frac{ 0.52 (1- 0.52 )}{563} }$

=> $\sigma = 0.02106$

Generally the probability that the proportion of persons with a college degree will differ from the population proportion by less than 5% is mathematically represented as

$P(| \^ p - p| < 0.05 ) = P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 ))$

Here $\^ p$ is the sample proportion of persons with a college degree.

$P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(\frac{[[0.05 -0.52]]- 0.52}{0.02106} < \frac{[\^p - p] - p}{\sigma } < \frac{[[0.05 -0.52]] + 0.52}{0.02106} )$

Here

$\frac{[\^p - p] - p}{\sigma } = Z (The\ standardized \ value \ of\ (\^ p - p))$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P[\frac{-0.47 - 0.52}{0.02106 } < Z < \frac{-0.47 + 0.52}{0.02106 }]$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P[ -2.37 < Z < 2.37 ]$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(Z < 2.37 ) - P(Z < -2.37 )$

From the z-table the probability of (Z < 2.37 ) and (Z < -2.37 ) is

$P(Z < 2.37 ) = 0.9911$

and

$P(Z < - 2.37 ) = 0.0089$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) =0.9911-0.0089$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = 0.9822$

=> $P(| \^ p - p| < 0.05 ) = 0.9822$

3 0

3 years ago

Find the slope and the y-intercept of the equation: 6y - 3x= -12

vivado [14]

Slope can be found but putting the equation in slope intercept form (y=mx+b)

6y=3x-12
y= 0.5x-2

M is your slope, b is the y intercept.

So the slope is 1/2, yintercept is (0,-2)

Hope this helps

7 0

3 years ago

What is the percentage of 0.39

Kitty [74]

Answer:

39%

Step-by-step explanation:

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a_sh-v [17]

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How do you factor the sum of 2 squares?

Kazeer [188]

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3 years ago