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Amanda [17]
3 years ago
15

How do you know where to place the decimal in a quotient?

Mathematics
2 answers:
stealth61 [152]3 years ago
6 0

It all depends on the divisor.

You need to make sure the decimal of the divisor is at the end.

For example, 2.09 divided by 0.19

You need to move the decimal point of 0.19 two times to the right so the decimal point is at the end.

If the divisor is a whole number, the decimal would stay at the same position.

For example, 25.5 divided by 5, the decimal would stay since 5's decimal point is already at the end (5.)

See attachment if you want to see it visual. Writing on computer is hard tho.

g100num [7]3 years ago
3 0

Answer:

Take note that the quotient's decimal point is precisely above the dividend's decimal point. To divide a decimal by a whole number, move the decimal point in the quotient above the decimal point in the dividend and divide as usual.

Step-by-step explanation:

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Factorise fully<br>-12a - 16 <br><br>please do quick, first to answer marked brainiest!!​
Allushta [10]

Answer:

-4( 3a+4)

Step-by-step explanation:

-12a - 16

-4*3a -4*4

Factor out a -4

-4( 3a+4)

3 0
3 years ago
Please I need help on this test
vovangra [49]

Answer:

y =  \frac{3}{2} x

y = 3

y - intercept =  - 3

slope =  - 1

Step-by-step explanation:

Hope this helps!

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6 0
3 years ago
Given the position of the particle, what the position(s) of the particle when it’s at rest
choli [55]

The position function of a particle is given by:

X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t

The velocity function is the derivative of the position:

\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}

The particle will be at rest when the velocity is 0, thus we solve the equation:

2t^2-9t-18=0

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

Substituting:

\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}

We have two possible answers:

\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

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6 0
1 year ago
2. Consider the following dot plot and answer the following questions : A. Find the measures of central tendency Construct the B
zubka84 [21]

The measures of central tendency for this data set are as follows:

  1. Mean = 3.55.
  2. Median = 3.5.
  3. Mode = 3.

<h3>How to calculate measures of central tendency?</h3>

In Mathematics, there are three (3) main measures of central tendency and these include the following:

  • Mean
  • Median
  • Mode

For the mean, we have:

Mathematically, the mean for this data set would be calculated by using this formula:

Mean = [F(x)]/n

For the total number of data, we have:

F(x) = 0 + 1 + 1 + 1 + 2 + 2 + 3 + 3 + 3 + 3 + 4 + 4 + 4 + 5 + 5 + 5 + 6 + 6 + 6 + 7

F(x) = 71

Substituting the parameters into the formula, we have:

Mean = [F(x)]/n

Mean = 71/20

Mean = 3.55.

For the median, we have:

First of all, we would order the data from lowest to highest and then determine the median as follows:

Data = {0, 1, 1, 1, 2, 2, 3, 3, 3,} 3, 4, {4, 4, 5, 5, 5, 6, 6, 6, 7}

Median = {3 + 4}/2

Median = 7/2

Median = 3.5.

<h3>How to calculate the mode?</h3>

A mode refers to the most frequently occurring number in a data set. Thus, the mode for this data set is equal to 3.

In conclusion, a box plot of the measures of central tendency for this data set is shown in the image attached below.

Read more on mean here: brainly.com/question/9550536

#SPJ1

6 0
2 years ago
How to do system of equations
aliya0001 [1]

Answer: The three methods most commonly used to solve systems of equation are substitution, elimination and augmented matrices.

Step-by-step explanation:

Substitution is a method of solving systems of equations by removing all but one of the variables in one of the equations and then solving that equation.

Elimination is another way to solve systems of equations by rewriting one of the equations in terms of only one variable. The elimination method achieves this by adding or subtracting equations from each other in order to cancel out one of the variables.

Augmented matrices can also be used to solve systems of equations. The augmented matrix consists of rows for each equation, columns for each variable, and an augmented column that contains the constant term on the other side of the equation.

7 0
3 years ago
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