Answer:
D
Step-by-step explanation:
x/(x²+3x+2) - 1/[(x+2)(x+1)]
x² + 3x + 2 = x² + 2x + x + 2
= x(x + 2) + (x + 2)
= (x + 2)(x + 1)
= x/[(x+2)(x+1)] - 1/[(x+2)(x+1)]
= (x-1)/[(x+2)(x+1)]
= (x-1)/(x²+3x+2)
Answer:
The Zscore for both test is the same
Step-by-step explanation:
Given that :
TEST 1:
score (x) = 75
Mean (m) = 65
Standard deviation (s) = 8
TEST 2:
score (x) = 75
Mean (m) = 70
Standard deviation (s) = 4
USING the relation to obtain the standardized score :
Zscore = (x - m) / s
TEST 1:
Zscore = (75 - 65) / 8
Zscore = 10/8
Zscore = 1.25
TEST 2:
Zscore = (75 - 70) / 4
Zscore = 5/4
Zscore = 1.25
The standardized score for both test is the same.
Answer: 8^14
8^10 x 8^4= 8^14
X=2
you multiply by 8 on both sides. so that your equation now looks like x-2=0
then you will add by 2 on both sides.
x=2
Answer:
3.5 more times sugar in B
Step-by-step explanation:
We need to see that the fact that Beverage B is 0.21 sugar can be translated to percentages, just by multiplying and dividing by 100 to get it easier to see:
0.21 * 100 /100 = 21/100 = 21% percent
This means that for every 100 units, 21 are sugar.
Now we can compare percentages directly, as both have the same volume because are sold in identical cans. We need to get how many times is 21 greater than 6. The only thing we need to do is the ratio between them:
21/6= 3.5
This implies that 21 is 3.5 greater than 6, you can verify it by multiplying 6 by 3.5 and getting 21.
So, B has 3.5 times more sugar than A.