Answer:
Relative frequency of selecting a 2 = 8/50 = 0.16
Relative frequency of selecting a 3 = 14/50 = 0.28
Step-by-step explanation:
When we have a given experiment with given outcomes (such that each time that we perform the experiment, one outcome happens) the relative frequency of a given outcome is the quotient between the number of times that that outcome happened, and the total number of times that the experiment was performed.
Here the experiment is selecting a random number between 1 and 5, and it is performed 50 times.
Out of these 50 times, the outcome "2" appears 8 times.
Then the relative frequency of selecting the number 2 is:
f(2) = 8/50 = 0.16
And of these 50 experiments, the outcome "3" appears 14 times.
Then the relative frequency of selecting the number 3 is:
f(3) = 14/50 = 0.28
I forgot how to do this sorry
There are 12 inches in a foot, so 9ft = 108in. Also, 80% = 0.8. Therefore the formula is:
h(n) = 108 * 0.8^n.
To find the bounce height after 10 bounces, substitute n=10 into the equation:
h(n) = 108 * 0.8^10 = 11.60in (2.d.p.).
Finally to find how many bounces happen before the height is less than one inch, substitute h(n) = 1, then rearrage with logarithms to solve for the power, x:
108 * 0.8^x = 1;
0.8^x = 1/108;
Ln(0.8^x) = ln(1/108);
xln(0.8) = ln(1\108);
x = ln(1/108) / ln(0.8) = -4.682 / -0.223 = 21 bounces
Answer:
$5,850
Step-by-step explanation:
4.5% = 0.045
0.045 x 130,000 = 5850
