Three of the angles of quadrilateral are 100 degrees, 104 degrees and 44 degrees. What is the size of the 4th angle

Quadrilateral RPQS is a rectangle. Label the missing measures.

Taya2010 [7]

Answer:

Part 1) $PR=9\ units$

Part 2) $PQ=12\ units$

Part 3) $PS=15\ units$

part 4) $QR=15\ units$

Part 5) $RT=7.5\ units$

Step-by-step explanation:

we know that

In a rectangle opposite sides are parallel and congruent

The measure of each interior angle is 90 degrees

The diagonals are congruent and bisect each other

step 1

Find the length of side PR

we know that

$PR=QS$ ----> by opposite sides

we have

$QS=9\ units$

therefore

$PR=9\ units$

step 2

Find the length of side PQ

we know that

$PQ=RS$ ----> by opposite sides

we have

$RS=12\ units$

therefore

$PQ=12\ units$

step 3

Find the length of diagonal PS

we know that

$PS=2PT$ ---> the diagonals bisect each other

we have

$PT=7.5\ units$ ---> given problem

therefore

$PS=2(7.5)=15\ units$

step 4

Find the length of diagonal QR

we know that

$QR=PS$ ---> the diagonals are congruent

we have

$PS=15\ units$

therefore

$QR=15\ units$

step 5

Find the length of RT

we know that

$QR=2RT$ ---> the diagonals bisect each other

we have

$QR=15\ units$

substitute

$15=2RT\\RT=7.5\ units$

7 0

3 years ago

Martin deposited $3,000 into an account that earned 3.5% simple interest over 7 years. What is the total value of the account fo

REY [17]

Answer:

the answer is d.

Step-by-step explanation: D

7 0

3 years ago

Read 2 more answers

Q4) Using Euclid's algorithm, find the HCF of 240 and 228

Free_Kalibri [48]

$\LARGE{ \underline{ \boxed{ \purple{ \rm{Solution : )}}}}}$

Euclid's division lemma : Let a and b are two positive integers. There exist unique integers q and r such that

a = bq + r, 0 $\leqslant$ r < b

Or We can write it as,

Dividend = Divisor × Quotient + Remainder

Work out:

Given integers are 240 and 228. Clearly 240 > 228. Applying Euclid's division lemma to 240 and 228,

⇛ 240 = 228 × 1 + 12

Since, the remainder 12 ≠ 0. So, we apply the division dilemma to the division 228 and remainder 12,

⇛ 228 = 12 × 19 + 0

The remainder at this stage is 0. So, the divider at this stage or the remainder at the previous age i.e 12

$\large{ \therefore{ \boxed{ \sf{HCF \: of \: 240 \: \& \: 228 = 12}}}}$

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8 0

3 years ago

Solve Ax − By = C for x.

Travka [436]

For this case we have the following equation:

$Ax - By = C$

From here, we must clear the value of x.

Adding By on both sides:

$Ax = By + C$

Then, dividing both sides by A we have:

$x = \frac {By + C} {A}$

Answer:

$x = \frac {By + C} {A}$

x equals the quantity B times and plus C all over A

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3 years ago

Shelly and Terrence completed a different number of tasks in a game. Shelly earned 90 points on each task. Terrence's total poin

Nat2105 [25]

The correct answer is A. The total points Shelly earned

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3 years ago