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3 years ago

A patio has an area of 20 5/6 ft, and the width of 3 1/2 ft. What is the length of the patio?

Mathematics

1 answer:

KATRIN_1 [288]3 years ago

3 0

The length of the patio would be approximately 5.95

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Aisha ate 1/4 of the carrots in the bag. Enrique ate 3/12 of the carrots in the bag. Compare the amounts of carrots they each at

Neko [114]

The amount of carrots they each ate are the same because 12 is a multiple of 4. There are 3 4’s in one 12. If you multiply 1/4 times 3 you will get 3/12 because 1 x 3 = 3. And 4 x 3 = 12

7 0

3 years ago

The interquartile range (IQR) for the data: 32,7,3,-5,1,8 , 10,36 is :

GenaCL600 [577]

Answer:

Your Interquartile range (IQR) would be 19.

Step-by-step explanation:

-5, 1, 3, 7, 8, 10, 32, 36

Median: 7.5

Lower quartile: 2

Upper quartile: 21

Interquartile range: 21 - 2 = 19

7 0

3 years ago

Cory found a job listed in a classified that pays a yearly salary of $54,013. What is the biweekly

Anon25 [30]

Answer:

2077.42

Step-by-step explanation:

There are 52 weeks in a year, so there are 26 "biweekly" weeks in a year.

Cory receieves $54013 per year, so he gets 54013 / 26 dollars biweekly.

We can compute that number, getting 2077.42 dollars.

5 0

3 years ago

mei has 15 oranges,9 peaches, and 18 pears. she wants to put all of the fruit into decorative baskets, what's the greats number

pashok25 [27]

Answer:

15,9,8 can be divided by 3

so, the greatest number of fruit in each basket is 3 Step-by-step explanation:

6 0

3 years ago

Will mark brainliest! Questions are in the picture!

alexdok [17]

Answer:

52.9 inches .

Step-by-step explanation:

Given that the triangular indentation has an area of 100 in.² and the base and height of this traingle are represented by expressions 3x and x+3 respectively . We need to find out the perimeter to the nearest tenth.

As we know that the area of triangle is ,

$\rm\longrightarrow Area_{\triangle}=\dfrac{1}{2}(base)(height)$

Substituting the respective values,

$\rm\longrightarrow 100\ =\dfrac{1}{2}(x+3)(3x)\\\\\rm\longrightarrow 2(100) = 3x(x+3)\\\\\rm\longrightarrow200 = 3x^2+9x\\\\\rm\longrightarrow 3x^2+9x-200=0$

On using the Quadratic formula , we have;

$\rm\longrightarrow x =\dfrac{-9\pm\sqrt{9^2-4(3)(-200)}}{2(3)} \\\\\rm\longrightarrow x =\dfrac{-9\pm \sqrt{81+1200}}{6}\\\\\rm\longrightarrow x =\dfrac{-9\pm \sqrt{1281}}{6}$