All categories

2 years ago

А square tile has a width of foot. How many tiles will fit end-to-end along a 4-foot wall?

Mathematics

2 answers:

levacccp [35]2 years ago

8 0

4 tiles

It’ll take four tiles to do it you just take the width which is 1 foot divided by the wall length

irina1246 [14]2 years ago

5 0

Answer:

4 tiles

Step-by-step explanation:

4/1 = 4

You might be interested in

A cookie jar contains 3 vanilla, 2 chocolate chip, and 7 gingersnap cookies. If one cookie is taken at random from the jar, what

horrorfan [7]

Answer:

3/12= 1/4

Step-by-step explanation: because you would add the all up for 12 and you have a 3 vanilla's so 3/12= 1/4

8 0

3 years ago

The junior and senior students at Mathville High School are going to present an exciting musical entitled, "Math, What is it Goo

xeze [42]

Some parts are missing in the queston. Find attached the picture with the complete question

Answer:

$\large\boxed{\large\boxed{161}}$

Explanation:

Let's put the information in a table step-by step.

(number of remaining students)

Juniors Seniors

Condition

Initially J S

15 seniors left S - 15

Twice juniors as seniors 2(S - 15)

3/4 of the juniors left 1/4×2(S - 15)
1/3 of seniors left 2/3×(S - 15)

At the end, there were 8 more seniors than juniors:

2/3×(S - 15) - 1/4×2(S - 15) = 8

Now you have obtained one equation, which you can solve to find S, the number of senior students, and then the number of junior students.

Solve the equation:

$2/3\times (S - 15) - 1/4\times 2(S - 15) = 8$

Mutilply all by 12:

$8(S - 15)-6(S - 15)=96$

Distribution property:

$8S-120-6S-90=96$

Addtion property of equalities:

$8S-6S=96+120+90$

Add like terms:

$2S=306$

Division property of equalities:

$S=306/2=153$

That is the number of senior students that came out to the information meeting, but the number of students remaining to perform in the school musical is (from the table above):

$2/3\times (S-15)+1/4\times 2(S-15)$

Just substitute S with 153 fo find the number of students that remained to perfom in the musical:

$2/3\times (153-15)+1/4\times 2(153-15)\\ \\ 2/3(138)+1/2(138)$

$161$

5 0

3 years ago

23 ones x 2 tens= answer

shutvik [7]

23 and 2 tens is 23 and 20 which equals 53

53

5 0

3 years ago

PLEASE HELP ASAP!!!!

lina2011 [118]

<h3>Answer:</h3>

System

p + m = 10
0.8m = 0.4·10

Solution

p = m = 5 — 5 lb peanuts and 5 lb mixture

<h3>Step-by-step explanation:</h3>

(a) Generally, the equations of interest are one that models the total amount of mixture, and one that models the amount of one of the constituents (or the ratio of constituents). Here, there are two constituents and we are given the desired ratio, so three different equations are possible describing the constituents of the mix.

For the total amount of mix:

... p + m = 10

For the quantity of peanuts in the mix:

... p + 0.2m = 0.6·10

For the quantity of almonds in the mix:

... 0.8m = 0.4·10

For the ratio of peanuts to almonds:

... (p +0.2m)/(0.8m) = 0.60/0.40

Any two (2) of these four (4) equations will serve as a system of equations that can be used to solve for the desired quantities. I like the third one because it is a "one-step" equation.

So, your system of equations could be ...

p + m = 10
0.8m = 0.4·10

___

(b) Dividing the second equation by 0.8 gives

... m = 5

Using the first equation to find p, we have ...

... p + 5 = 10

... p = 5

5 lb of peanuts and 5 lb of mixture are required.

8 0

3 years ago

How do you solve common core math when it asks you to write the first step question and answer?

slega [8]

Represent addition and subtraction with objects, fingers, mental images, drawings1, sounds (e.g., claps), acting out situations, verbal explanations, expressions, or equations.

7 0

3 years ago