No, Yes, No, Yes
using the laws of exponents
(1)
(
)³ = 
4³ × 4³ = 
≠
→ No
(2)
(
)^4 = 
×
=
→ Yes
(3)
= (6 × 3 )^8 =
×
≠
×
→ No
(4)
= (4 × 5 )³ = 4³ × 5³ → Yes
52/8 = 6
6*8 = 48
52-48 = 4
So 52 = 6*8+4
The quotient is 6, the remainder is 4.
The answer is b
Because you have to add da x and dat is 2x den add da numbers which is 4
I'm sorry but I know the answer is deffinetly c or d
Answer:
<h2>For c = 5 → two solutions</h2><h2>For c = -10 → no solutions</h2>
Step-by-step explanation:
We know

for any real value of <em>a</em>.
|a| = b > 0 - <em>two solutions: </em>a = b or a = -b
|a| = 0 - <em>one solution: a = 0</em>
|a| = b < 0 - <em>no solution</em>
<em />
|x + 6| - 4 = c
for c = 5:
|x + 6| - 4 = 5 <em>add 4 to both sides</em>
|x + 6| = 9 > 0 <em>TWO SOLUTIONS</em>
for c = -10
|x + 6| - 4 = -10 <em>add 4 to both sides</em>
|x + 6| = -6 < 0 <em>NO SOLUTIONS</em>
<em></em>
Calculate the solutions for c = 5:
|x + 6| = 9 ⇔ x + 6 = 9 or x + 6 = -9 <em>subtract 6 from both sides</em>
x = 3 or x = -15