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Anvisha [2.4K]
3 years ago
9

Help please and thank you (is also my bday haha)

Mathematics
1 answer:
Marysya12 [62]3 years ago
5 0

Answer:

the center point of the cross in the middle

Step-by-step explanation:

I forgot how to explain it, but im 99.99% sure thats the right answer. also, happy birthday

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Solve for x: 5/x^2-4+2/x=2/x-2
IRINA_888 [86]

\dfrac{5}{x^2 - 4} + \dfrac{2}{x} = \dfrac{2}{x - 2}


\dfrac{5}{(x + 2)(x - 2)} + \dfrac{2}{x} = \dfrac{2}{x - 2}


\dfrac{5}{(x + 2)(x - 2)} \times x(x + 2)(x - 2) + \dfrac{2}{x} \times x(x + 2)(x - 2) = \dfrac{2}{x - 2} \times x(x + 2)(x - 2)


5x + 2(x + 2)(x - 2) = 2x(x + 2)


5x + 2(x^2 - 4) = 2x^2 + 4x


5x + 2x^2 - 8 = 2x^2 + 4x


5x - 8 = 4x


x - 8 = 0


x = 8


Now we look at the common denominator.

It is x(x + 2)(x - 2).

x cannot be zero, -2 or 2 because that would cause a zero in the denominator.

Since we get x = 8, and x = 8 does not have to be excluded from the domain, the answer is x = 8.


Answer: x = 8

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3 years ago
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perp. is -0 which is 0

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Step-by-step explanation:

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Step-by-step explanation:

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