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aliina [53]
3 years ago
8

What's the correct answers since i got em wrong​

Mathematics
1 answer:
Reptile [31]3 years ago
4 0

Answer: its not loading

Step-by-step explanation:

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The square root of the quotient of a number and 6 is 9. What is this number?
VARVARA [1.3K]
First, square both sides of equation so it ends up to be:
a/6=81
so 
a=27/2
4 0
4 years ago
Find the 5th term of the sequence which has a first of 1 and a common ratio of 2.3
sveticcg [70]
Hello : 

the nth term is :  An =A1 × r^(n-1)

A1 = 1      r = 2.3     n = 5

 A5 =1 × (2.3)^(5-1)=27.9841


3 0
4 years ago
How do I do this problem?
lions [1.4K]

Answer:

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5 0
3 years ago
Read 2 more answers
What are the solutions to the system of equations? {−x+y=4y+12=x2+x
Ulleksa [173]

Answer: (-4, 0) and (4, 8)

Step-by-step explanation:

Looking at the graph, we can see where the line passes the parabola and can tell the solutions are (-4, 0) and (4, 8)

8 0
2 years ago
Work out the area of the trapezium ABDE.<br> B<br> 9 cm<br> 6 cm<br> 8 cm<br> →D<br> E
Evgen [1.6K]

Answer:

Area of the trapezium ABDE = 30 cm²

Step-by-step explanation:

Area of a trapezium = \frac{1}{2}(b_1+b_2)h

Here, b_1 and b_2 are the parallel sides of the trapezium

h = Distance between the parallel sides

From the picture attached,

ΔCAE and ΔCBD are the similar triangles.

So by the property of similarity their sides will be proportional.

\frac{AE}{BD}= \frac{CE}{CD}

\frac{9}{6}=\frac{CE}{8}

CE = \frac{9\times 8}{6}

CE = 12 cm

Therefore, DE = CE - CD

DE = 12 - 8 = 4 cm

Now area of trapezium ABDE = \frac{1}{2}(AE+BD)(DE)

                                                  = \frac{1}{2}(6+9)4

                                                  = 30 cm²

Therefore, area of the trapezium ABDE = 30 cm²

8 0
3 years ago
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