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sashaice [31]
3 years ago
7

Which fraction is equal to 2/3 is it 4/14, 6/9, 5/15

Mathematics
2 answers:
madreJ [45]3 years ago
8 0
It would be 6/9, because if you multiply the numerator and denominator (2/3) by 3, it would equal to 6/9
GalinKa [24]3 years ago
4 0
The answer is 6/9 as if you multiply 2/3 by 3 you will get 6/9 so it has the same value
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What number would represent the outlier in the following set of data?
Mademuasel [1]
I think it is 29 cause it’s in the 20’s while the others aren’t
5 0
3 years ago
3 x one half<br><br><br> three halves<br><br> five sixths<br><br> one sixth<br><br> one half
fomenos

Answer:

three halves

Step-by-step explanation:

1/2 * 3 = 3/2 = 1 1/2 = 1.5

Multiple: 1/2 * 3 = 1 · 3/2 · 1 = 3/2

Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD(3, 2) = 1. In the following intermediate step, it cannot further simplify the fraction result by canceling.

In other words - one half multiplied by three = three halfs.

3 0
2 years ago
Please answer the file question.
viktelen [127]

Answer:48 16 = ?

27 9 = 9

60 20 - 10

Step-by-step explanation:

4 0
3 years ago
Please help! 5 Points. Hurry!
larisa [96]
<h2>Answer:</h2>

<u>The correct option is 3x + 4y = 10</u>

<h2>Step-by-step explanation:</h2>

The standard form for any linear equations having two variables is written as Ax+By=C. For example, 3x+4y=10 is a linear equation in standard form. When an equation is given in this form, it becomes easy to find both intercepts (x and y). This form is also very useful when solving systems of two linear equations whose solution is required to find the point of intersection of given lines.

7 0
4 years ago
HELP PLEASEEEEEEEEEeeeee
maks197457 [2]
Might have to experiment a bit to choose the right answer.

In A, the first term is 456 and the common difference is 10.  Each time we have a new term, the next one is the same except that 10 is added.

Suppose n were 1000.  Then we'd have 456 + (1000)(10) = 10456

In B, the first term is 5 and the common ratio is 3.  From 5 we get 15 by mult. 5 by 3.  Similarly, from 135 we get 405 by mult. 135 by 3.  This is a geom. series with first term 5 and common ratio 3.   a_n = a_0*(3)^(n-1).
So if n were to reach 1000, the 1000th term would be 5*3^999, which is a very large number, certainly more than the 10456 you'd reach in A, above.

Can you now examine C and D in the same manner, and then choose the greatest final value?  Safe to continue using n = 1000.





3 0
3 years ago
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