Answer:
= 3b/4
Step-by-step explanation:
= b . 4/12 + b . 3/12 + b . 2/12
Apply the fraction rule: a/c + b/c = a + b/c
= b . 4 + b . 3 + b . 2/12
= 4b + 3b + 2b/12
Add similar elements: 4b + 3b + 2b = 9b
= 9b/12
Cancel 9b/12: 3b/4
= 3b/4
Answer:
b is the answer by solomon
To find the z-score for a weight of 196 oz., use

A table for the cumulative distribution function for the normal distribution (see picture) gives the area 0.9772 BELOW the z-score z = 2. Carl is wondering about the percentage of boxes with weights ABOVE z = 2. The total area under the normal curve is 1, so subtract .9772 from 1.0000.
1.0000 - .9772 = 0.0228, so about 2.3% of the boxes will weigh more than 196 oz.
Answer:
Step-by-step explanation:
B is the answer pretty sure
Answer:
1)
1111 = 0.7
2)
1010 = 0.10
Above one is the binary method But if you need another method it will be like this...... (but most likely follow the above (binary) method.)
1)
1111/1000
0.1111
2)
1010/1000
0.1010
Hope it helped u if yes mark me BRAINLIEST