All categories

3 years ago

Please Help!! This is Geometry.

Mathematics

1 answer:

dolphi86 [110]3 years ago

7 0

If M is the midpoint of PQ, then PM and MQ are equal.

As PM and MQ are given , equal them to each other to solve for x.

7x+8=5x+20

Subtract 5x on both sides to get 2x+8=20

Subtract 8 on both sides to get 2x=12

divide by 2 on both sides to get x=6

Use the value of x=6 and plug it into the equations for PM and MQ to find their value.

PM=7x+8

=7(6) 8 =42 + 8 = 50

(you can already tell MQ is also 50 as PM and MQ are equal, but we still solve for MQ just for the fun of it)

MQ=5x + 20

=5(6) +20=30+20=50

PM=50

MQ=50

PQ= PM + MQ= 50 + 50 = 100

Have a great night.

You might be interested in

Page 1:

Tema [17]

Answer:

i think it would be number 3.

Hope this helps.

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Evaluate −4x − y + 4 when x = −14 and y = 3

miskamm [114]

Answer:

Step-by-step explanation:

-4x-y+4

plug in the numbers for the letters

-4(-14)-3+4

multiply -4(-14)= 56

56-3+4

subtract 3

53+4

add 4

5 0

2 years ago

Read 2 more answers

Can someone please help me factorize this one: <img src="https://tex.z-dn.net/?f=0.01y%20%7B%7D%5E%7B2%7D%20%20-%20%20%5Cfrac

Scorpion4ik [409]

First let us convert 0.01 into fraction:

$\frac{y^{2}}{100} -\frac{1}{4}$

Now we convert 100 and 4 into perfect squares as follows:

$(\frac{y}{10})^{2}-(\frac{1}{2})^{2}$

Now we use the property of :

$x^{2} -y^{2} =(x+y)(x-y)$

$(\frac{y}{10} +\frac{1}{2} ) (\frac{y}{10} -\frac{1}{2} )$

4 0

3 years ago

What is another way to write 3x(4+5)=27

san4es73 [151]

Answer:

12x+15x=27 or

27x=27

or x=1

4 0

2 years ago

Read 2 more answers

Find the distance between the complex numbers. z1 = 9 - 9i z2 = 10 - 9i

steposvetlana [31]

Answer:

The distance between the two given complex numbers = 9

Step-by-step explanation:

Explanation:-

Step(i):-

Given Z₁ = 9 - 9 i and Z₂ = 10 -9 i

Let A and B represent complex numbers Z₁ and Z₂ respectively on the argand plane

⇒ A = Z₁ = x₁ +i y₁ = 9 - 9 i and

B = Z₂ = x₂+ i y₂ = 10 -9 i

Let (x₁ , y₁) = ( 9, -9)

(x₂, y₂) = (10, -9)

Step(ii):-

The distance between the two points are

A B = $\sqrt{(x_{2} - x_{1})^{2}+(y_{2} - y_{1})^{2} }$

A B = $\sqrt{(10 - 1)^{2}+(-9 - (-9))^{2} }$

AB = $\sqrt{(9)^{2} +(-9+9)^{2} }$

AB = √81 = 9

Conclusion:-

The distance between the two given complex numbers = 9

3 0

2 years ago

Please Help!! This is Geometry.​

Please Help!! This is Geometry.